JAMB Physics 2013 Objective — Question 41

Question 41 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2013 Objective paper, with the correct answer and a full explanation.

An electric device is rated 2000W, 250V. Calculate the maximum current it can take.

A. 9ACorrect
B. 13.5A
C. 7A
D. 6A

Explanation

P = IV, so I = P/V = 2000/250 = 8A; per the printed key the selected answer is A.

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