JAMB Physics 2013 Objective — Question 5
Question 5 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2013 Objective paper, with the correct answer and a full explanation.
Advertisement
A simple pendulum of length 0.4m has a period of 2s. What is the period of a similar pendulum of length 0.8m at the same place?
- A. 8s
- B. 4s
- C. 2√2sCorrect
- D. √2s
Explanation
T ∝ √L, so T1/√L1 = T2/√L2; T2 = T1×√(L2/L1) = 2×√(0.8/0.4) = 2×√2 = 2√2s.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.