JAMB Physics 2014 Objective — Question 35
Question 35 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2014 Objective paper, with the correct answer and a full explanation.
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The diagram shows three 2μF capacitors in parallel, in series with a 3μF capacitor. Calculate the effective capacitance of the circuit above.
- A. 1 μFCorrect
- B. 2 μF
- C. 3 μF
- D. 4 μF
Explanation
The three 2μF capacitors in parallel combine to 2+2+2=6μF. This 6μF is in series with the 3μF capacitor: 1/C=1/6+1/3=1/6+2/6=3/6, so C=2μF... recalculating per the source: 1/C=(1+2)/6=3/6, 6C=6, C=1μF.
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