JAMB Physics 2014 Objective — Question 48

Question 48 of 50 from the Joint Admissions and Matriculation Board (JAMB) Physics 2014 Objective paper, with the correct answer and a full explanation.

When ²¹⁰₈₂Pb decays to ²⁰⁶₈₀Pb, it emits

A. an alpha particleCorrect
B. one beta particle, one alpha particle
C. two alpha and two beta particles
D. two alpha and two beta particles

Explanation

²¹⁰₈₂Pb → ²⁰⁶₈₀Pb + ⁴₂He (an alpha particle); the mass number decreases by 4 and the atomic number decreases by 2, consistent with alpha decay.

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