JAMB Physics 2019 Objective — Question 4
Question 4 of 40 from the Joint Admissions and Matriculation Board (JAMB) Physics 2019 Objective paper, with the correct answer and a full explanation.
Advertisement
A force of 14N is applied to a spring of stiffness 220N/m. Calculate the energy stored in the spring
- A. 3080J
- B. 15.71J
- C. 0.4455JCorrect
- D. 0.02835J
Explanation
Extension e=F/K=14/220=0.06364m. Energy stored = ½Fe = ½×14×0.06364 = 0.4455J.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.