Free account: track your progress — Sign up free

JAMB Physics 2020 Objective — Question 34

Question 34 of 40 from the Joint Admissions and Matriculation Board (JAMB) Physics 2020 Objective paper, with the correct answer and a full explanation.

Advertisement

34. 250g of lead at 170°C is dropped into 100g of water at 0°C. If the final temperature is 12°C, the specific heat capacity of lead is (S.H.C of water = 4200J/kg°C)

  • A. A. 39.5J/kg°C
  • B. B. 50.4J/kg°C
  • C. C. 127.6J/kg°CCorrect
  • D. D. 154J/kg°C

Explanation

Heat lost by lead = heat gained by water: 0.25 x C_lead x (170-12) = 0.1 x 4200 x (12-0). 0.25 x C_lead x 158 = 5040. 39.5 x C_lead = 5040. C_lead = 127.6J/kg°C.

Advertisement

Sign up free to unlock

  • Score tracking
  • Practice history
  • Saved questions
  • Progress dashboard
  • Personalized sessions
  • Weak-topic breakdown

…and/or go further with premium services and No Ads.