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JAMB Physics 2020 Objective Past Questions

All 40 questions from the Joint Admissions and Matriculation Board (JAMB) Physics 2020 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Physics 2020 Objective — Question 1

1. A pendulum which has a mass of 200g is pulled sideways by a horizontal distance of 30cm. If the length of the pendulum is 50cm, calculate the potential energy of the bob in this position (g=10m/s2)

  • A. A. 0.2JCorrect
  • B. B. 2.0J
  • C. C. 2.2J
  • D. D. 20J

Explanation

h = L - sqrt(L^2-x^2) = 0.5 - sqrt(0.25-0.09) = 0.5-0.4 = 0.1m. PE = mgh = 0.2x10x0.1 = 0.2J.

Physics 2020 Objective — Question 2

2. An object of mass 300kg and a density 600kg/m3 was suspended with a string so that half of it is immersed in paraffin of density 900kg/m3. What is the tension in the string? (g=9.8m/s2)

  • A. A. 2205N
  • B. B. 735NCorrect
  • C. C. 3000N
  • D. D. 2940N

Explanation

Volume = 300/600 = 0.5m3. Volume immersed = 0.25m3. Upthrust = 900x0.25x9.8 = 2205N. Weight = 300x9.8 = 2940N. Tension = Weight - Upthrust = 2940-2205 = 735N.

Physics 2020 Objective — Question 3

3. A car accelerates uniformly from rest at 4m/s2. How far will it travel in the fifth second?

  • A. A. 100m
  • B. B. 50m
  • C. C. 32m
  • D. D. 18mCorrect

Explanation

Distance in nth second = u + a(2n-1)/2 = 0 + 4(9)/2 = 18m.

Physics 2020 Objective — Question 4

4. The quantity of an object which is a measure of its tendency to continue in motion with a steady velocity is its

  • A. A. volume
  • B. B. density
  • C. C. massCorrect
  • D. D. weight

Explanation

Inertia (the tendency of a body to continue in motion at steady velocity, or remain at rest) is known as its physical property, and this depends on mass.

Physics 2020 Objective — Question 5

5. Which of the following combinations will increase the stability of an object?

  • A. A. wide base and low centre of gravityCorrect
  • B. B. Narrow base and low centre of gravity
  • C. C. Wide base and high centre of gravity
  • D. D. Narrow base and high centre of gravity

Explanation

The wider the base and the lower the position of centre of gravity of a body, the more stable it is (and vice-versa).

Physics 2020 Objective — Question 6

6. The physical quantity that has the same dimension as impulse is

  • A. A. momentumCorrect
  • B. B. pressure
  • C. C. energy
  • D. D. surface tension

Explanation

Impulse = force x time = mass x acceleration x time = mass x change in velocity = momentum. Both have dimension MLT^-1.

Physics 2020 Objective — Question 7

7. A disc rotates on a player at constant speed of 200 revolutions per minute. Determine the period of rotation.

  • A. A. 1.2s
  • B. B. 0.6s
  • C. C. 0.5s
  • D. D. 0.3sCorrect

Explanation

Speed = 200 revolutions per minute = 200/60Hz = 3.3333Hz. T = 1/f = 1/3.3333 = 0.3s.

Physics 2020 Objective — Question 8

8. A lorry travels 10km northwards, 5km eastwards, 4km southwards and then finally 5km westwards. What is the total displacement?

  • A. A. 24km due north
  • B. B. 6km due south
  • C. C. 6km due northCorrect
  • D. D. 4km due south

Explanation

Net north-south: 10km N - 4km S = 6km N. Net east-west: 5km E - 5km W = 0. Total displacement = 6km due north.

Physics 2020 Objective — Question 9

9. A rocket is held fixed so that it ejects material horizontally with a speed of 150m/s. If it ejects a mass of 1.2kg/s, calculate the force needed to hold it fixed.

  • A. A. 180NCorrect
  • B. B. 120N
  • C. C. 150N
  • D. D. 40N

Explanation

Force = mass flow rate x velocity of exhaust = 1.2 x 150 = 180N.

Physics 2020 Objective — Question 10

10. A hygrometer is an instrument for measuring the

  • A. A. depth of water in a vessel
  • B. B. relative humidity of the airCorrect
  • C. C. relative density of a liquid by the method of flotation
  • D. D. atmospheric pressure

Explanation

A hygrometer is used for measuring the relative humidity of the air, while a hydrometer is used for measuring the relative density of a liquid by the method of flotation.

Physics 2020 Objective — Question 11

11. A uniform metre rule of weight 1.0N is pivoted at the 40cm mark. A weight of 2N is hung from the 15cm mark. Where must a weight of 2N be placed to balance the rule?

  • A. A. 20cm mark
  • B. B. 60cm markCorrect
  • C. C. 50cm mark
  • D. D. 40cm mark

Explanation

Taking moments about the pivot (40cm mark): Clockwise moment = Anticlockwise moment. 1x(50-40) + 2x(x-40) = 2x(40-15). 10+2x-80=50. 2x=120. x=60cm mark.

Physics 2020 Objective — Question 12

12. A wheel and axle is used to raise a load of 500N by the use of an effort of 250N. Determine the efficiency of the machine if the radii of the wheel and axle are respectively 0.4cm and 0.1cm

  • A. A. 60%
  • B. B. 50%Correct
  • C. C. 40%
  • D. D. 20%

Explanation

Velocity ratio = radius of wheel/radius of axle = 0.4/0.1 = 4. Mechanical advantage = load/effort = 500/250 = 2. Efficiency = (MA/VR) x 100% = (2/4)x100% = 50%.

Physics 2020 Objective — Question 13

13. For what celsius temperature is the reading on the celsius scale equal to that on the fahrenheit scale?

  • A. A. -80°C
  • B. B. 80°C
  • C. C. -40°CCorrect
  • D. D. 40°C

Explanation

F=9/5C+32. Setting F=C=x: x=9/5x+32 → -4/5x=32 → x=-40. So -40°C corresponds to -40°F.

Physics 2020 Objective — Question 14

14. Which of these waves cannot be polarized?

  • A. A. sound waves
  • B. B. light waves
  • C. C. all longitudinal wavesCorrect
  • D. D. all mechanical waves

Explanation

Polarization is an exclusive property of transverse waves. All longitudinal waves (including sound waves) cannot be polarized.

Physics 2020 Objective — Question 15

15. A concave mirror of radius of curvature 20cm forms a real image four times as large as the object. The object distance is

  • A. A. 60cm
  • B. B. 40cm
  • C. C. 30cm
  • D. D. 12.5cmCorrect

Explanation

f=r/2=10cm. Since magnification M=v/u=4, v=4u. Using mirror formula 1/f=1/v+1/u: 1/10=1/4u+1/u=5/4u. 4u=50. u=12.5cm.

Physics 2020 Objective — Question 16

16. What is the resistance that must be placed in parallel with a 25Ω to make a combined resistance of 15Ω

  • A. A. 45Ω
  • B. B. 37.5ΩCorrect
  • C. C. 35.7Ω
  • D. D. 35Ω

Explanation

1/15 = 1/25 + 1/x. 1/x = 1/15-1/25 = (5-3)/75 = 2/75. x = 37.5Ω.

Physics 2020 Objective — Question 17

17. The distance between the object and the pinhole of a pinhole camera is reduced by a factor of 4. The size of the imaged

  • A. A. is quadrupledCorrect
  • B. B. is reduced to a quarter
  • C. C. is doubled
  • D. D. remains unchanged

Explanation

Magnification (image size/object size) = image distance/object distance. Since object distance is reduced by a factor of 4, the magnification (and hence image size, for fixed screen/image distance) increases fourfold — the image is quadrupled.

Physics 2020 Objective — Question 18

18. Which of the following combinations will not produce white light after mixing?

  • A. A. Blue & magentaCorrect
  • B. B. Red, green & blue
  • C. C. Yellow & blue
  • D. D. Red & cyan

Explanation

Red+cyan, blue+yellow, and green+magenta are complementary colour pairs that produce white light when mixed, as does red+green+blue. Blue & magenta is not a standard complementary pair that produces white.

Physics 2020 Objective — Question 19

19. If a current of 4A is passed through a thin cable for two hours, how much electrical energy will be converted to heat energy, given that the electrical resistance of the cable is 10 ohms?

  • A. A. 4.25MJ
  • B. B. 2.15MJ
  • C. C. 1.95MJ
  • D. D. 1.15MJCorrect

Explanation

H = I^2Rt = 4^2 x 10 x (2x3600)s = 16x10x7200 = 1,152,000J ≈ 1.15MJ.

Physics 2020 Objective — Question 20

20. Which of the following statements is true about Coulomb's law?

  • A. A. states that the force of attraction or repulsion is directly proportional to the square of the distance between two charges
  • B. B. states that the force of attraction or repulsion is directly proportional to the distance between two charges
  • C. C. is a direct square law
  • D. D. is an inverse square lawCorrect

Explanation

Coulomb's law states that the force of attraction or repulsion between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them — it is an inverse square law.

Physics 2020 Objective — Question 21

21. An object initially at a distance of 10cm from a plane mirror moves at a speed of 10cm/s away from the mirror. What would be the distance between the object and the image after 5s?

  • A. A. 1.2mCorrect
  • B. B. 60cm
  • C. C. 50cm
  • D. D. 20cm

Explanation

Additional distance moved in 5s = 10x5 = 50cm. New object distance = 10+50 = 60cm. Image distance (plane mirror) = object distance = 60cm. Distance between object and image = 60+60 = 120cm = 1.2m.

Physics 2020 Objective — Question 22

22. Two mirrors in a barber's shop are on the walls opposite to each other. A man seated in between the mirrors will see how many images of himself?

  • A. A. 2
  • B. B. 3
  • C. C. 4
  • D. D. InfiniteCorrect

Explanation

For two mirrors placed exactly opposite (parallel) to each other, the angle between them is 0°, producing an infinite number of images.

Physics 2020 Objective — Question 23

23. Which of the following pairs contains one vector and one scalar quantity?

  • A. A. Displacement and acceleration
  • B. B. Force and kinetic energyCorrect
  • C. C. Momentum and velocity
  • D. D. Power and speed

Explanation

Force is a vector while kinetic energy is a scalar. Displacement and acceleration are both vectors; momentum and velocity are both vectors; power and speed are both scalars.

Physics 2020 Objective — Question 24

24. The process of adding impurity to a semi-conductor to increase its conductivity is called

  • A. A. dopingCorrect
  • B. B. annealing
  • C. C. ionizing
  • D. D. hardening

Explanation

The process of adding impurity to a semiconductor to increase its conductivity is called doping. The resulting semiconductor is known as an extrinsic (impure) semiconductor.

Physics 2020 Objective — Question 25

25. A vibrating string has a tension of 40N and produces a note of 200Hz when plucked in the middle. If the length of the string is unaltered and the tension is increased to 160N, the frequency becomes

  • A. A. 200Hz
  • B. B. 400HzCorrect
  • C. C. 800Hz
  • D. D. 50Hz

Explanation

Frequency is proportional to the square root of tension (length unaltered). f2 = f1 x sqrt(T2/T1) = 200 x sqrt(160/40) = 200 x 2 = 400Hz.

Physics 2020 Objective — Question 26

26. The equation of a travelling wave is given by y=2sin(4πx-25πt), the frequency of the wave is

  • A. A. 1.25Hz
  • B. B. 4Hz
  • C. C. 12.5HzCorrect
  • D. D. 50Hz

Explanation

Comparing with y=Asin(kx-ωt): ω=25π=2πf, so f=12.5Hz.

Physics 2020 Objective — Question 27

27. The process of adding impurity to a semi-conductor to increase its conductivity is called (repeat reference)

  • A. A. dopingCorrect
  • B. B. force
  • C. C. heating
  • D. D. hardening

Explanation

Same as Q24 — this is doping, producing an extrinsic semiconductor.

Physics 2020 Objective — Question 28

28. A stone which is dropped into a dry well hits the bottom in 2.2s. How deep is the well?

  • A. A. 2.4m
  • B. B. 24.2mCorrect
  • C. C. 40.4m
  • D. D. 48.4m

Explanation

s = ut + (1/2)at^2 = 0 + 0.5x10x2.2^2 = 0.5x10x4.84 = 24.2m.

Physics 2020 Objective — Question 29

29. A boy holds the end of a rubber cord from which hangs a solid metal ball. If the boy whirls the ball in a horizontal circle, keeping his hand still, in what direction will the ball move when the cord breaks?

  • A. A. Towards the hand of the boy
  • B. B. Away from the hand of the boy
  • C. C. In the direction of the tangent to the circle at the point of breakCorrect
  • D. D. None of the above

Explanation

When the cord breaks, the centripetal force is removed, so the ball moves in a straight line in the direction of the tangent to the circle at the point of break (Newton's first law).

Physics 2020 Objective — Question 30

30. 50g of water at 20°C is added to 200g of water at 80°C. If properly stirred, determine the temperature of the mixture.

  • A. A. 40°C
  • B. B. 56°C
  • C. C. 68°CCorrect
  • D. D. 86°C

Explanation

Heat lost by hot water = heat gained by cold water: 200(80-x) = 50(x-20). 16000-200x=50x-1000. 17000=250x. x=68°C.

Physics 2020 Objective — Question 31

31. When a ray of light passes from water to glass, it is

  • A. A. bent away from the normal
  • B. B. broken into a pure spectrum
  • C. C. absorbed by the glass
  • D. D. bent towards the normalCorrect

Explanation

When light passes from a less dense medium (water) to a denser medium (glass), it bends towards the normal.

Physics 2020 Objective — Question 32

32. The following frequencies are overtones of 140Hz except

  • A. A. 760HzCorrect
  • B. B. 420Hz
  • C. C. 560Hz
  • D. D. 840Hz

Explanation

Overtones of 140Hz are whole-number multiples: 280, 420, 560, 700, 840Hz etc. 760Hz is not a whole-number multiple of 140Hz (760/140 = 5 remainder 60), so it is not an overtone of 140Hz.

Physics 2020 Objective — Question 33

33. The quality of sound depends on

  • A. A. frequency
  • B. B. vibration
  • C. C. amplitude
  • D. D. harmonicsCorrect

Explanation

The pitch of a note depends on its frequency, the loudness depends on the amplitude, and the quality/timbre depends on the overtones/harmonics present.

Physics 2020 Objective — Question 34

34. 250g of lead at 170°C is dropped into 100g of water at 0°C. If the final temperature is 12°C, the specific heat capacity of lead is (S.H.C of water = 4200J/kg°C)

  • A. A. 39.5J/kg°C
  • B. B. 50.4J/kg°C
  • C. C. 127.6J/kg°CCorrect
  • D. D. 154J/kg°C

Explanation

Heat lost by lead = heat gained by water: 0.25 x C_lead x (170-12) = 0.1 x 4200 x (12-0). 0.25 x C_lead x 158 = 5040. 39.5 x C_lead = 5040. C_lead = 127.6J/kg°C.

Physics 2020 Objective — Question 35

35. A magnetic needle is suspended first at the earth's north magnetic pole and then at the point on the earth's magnetic equator. The respective angles between the needle and the horizontal are

  • A. A. 0° and 0°
  • B. B. 90° and 0°Correct
  • C. C. 0° and 90°
  • D. D. 90° and 90°

Explanation

The angle of dip is 90° at the magnetic poles and 0° at the magnetic equator.

Physics 2020 Objective — Question 36

36. The linear expansivity of brass is 2x10^-5°C^-1. If the volume of a piece of brass is 10cm3 at 0°C, what will be its volume at 100°C?

  • A. A. 10.06cm3Correct
  • B. B. 10.04cm3
  • C. C. 10.02cm3
  • D. D. 10.20cm3

Explanation

Cubic expansivity ≈ 3 x linear expansivity = 6x10^-5°C^-1. V2 = V1(1+3α∆θ) = 10(1+6x10^-5x100) = 10(1.006) = 10.06cm3.

Physics 2020 Objective — Question 37

37. The resistance of a wire depends on

  • A. A. the length of the wire
  • B. B. the diameter of the wire
  • C. C. the resistivity of the wire
  • D. D. all of the aboveCorrect

Explanation

Resistance R=ρl/A, so it depends on the resistivity (ρ), length (l), and area/diameter (A) of the wire.

Physics 2020 Objective — Question 38

38. A given mass of an ideal gas occupies a volume V at a temperature T and under a pressure P. If the pressure is increased to 2P and the temperature reduced to (1/2)T, the percentage change in the volume of the gas is

  • A. A. 0%
  • B. B. 25%
  • C. C. 75%Correct
  • D. D. 300%

Explanation

Using PV/T=constant: (2P)(V2)/(T/2) = PV/T → V2 = V/4. The volume decreases from V to V/4, a decrease of 3V/4, i.e. a 75% decrease.

Physics 2020 Objective — Question 39

39. When a sound wave passes from air into water, its

  • A. A. speed and frequency increase but wavelength remains the same
  • B. B. speed and wavelength increase but frequency remains the sameCorrect
  • C. C. speed remains the same but wavelength and frequency increase
  • D. D. speed decreases while wavelength and frequency increase

Explanation

When sound passes from air to water, only the speed and wavelength change (both increase); the frequency remains the same since it is determined by the source.

Physics 2020 Objective — Question 40

40. A wave of frequency 10Hz forms a stationary wave pattern in a medium where the velocity is 0.2m/s. Calculate the distance between adjacent nodes.

  • A. A. 1.0cmCorrect
  • B. B. 2.0cm
  • C. C. 1.5cm
  • D. D. 3.0cm

Explanation

λ = v/f = 0.2/10 = 0.02m = 2cm. Distance between adjacent nodes = λ/2 = 1.0cm.

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