JAMB Physics 2020 Objective — Question 40
Question 40 of 40 from the Joint Admissions and Matriculation Board (JAMB) Physics 2020 Objective paper, with the correct answer and a full explanation.
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40. A wave of frequency 10Hz forms a stationary wave pattern in a medium where the velocity is 0.2m/s. Calculate the distance between adjacent nodes.
- A. A. 1.0cmCorrect
- B. B. 2.0cm
- C. C. 1.5cm
- D. D. 3.0cm
Explanation
λ = v/f = 0.2/10 = 0.02m = 2cm. Distance between adjacent nodes = λ/2 = 1.0cm.
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