Post-UTME Mathematics 2011 Objective — Question 4
Question 4 of 11 from the Post-UTME Screening (Post-UTME) Mathematics 2011 Objective paper, with the correct answer and a full explanation.
Advertisement
Find the equation of a line perpendicular to the line 3x+2y+4=0 and passing through the point (5,6).
- A. 3x+2y-27=0
- B. 2x+3y+8=0
- C. 2x-3y+8=0Correct
- D. 3x+2y=-8
Explanation
The perpendicular gradient to -3/2 is 2/3. Using point (5,6): y-6=(2/3)(x-5), giving 3y-18=2x-10, i.e. 2x-3y+8=0.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.