Post-UTME Mathematics 2011 Objective — Question 5
Question 5 of 11 from the Post-UTME Screening (Post-UTME) Mathematics 2011 Objective paper, with the correct answer and a full explanation.
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Two perpendicular lines PQ and QR intercept at (1,-1). If the equation of PQ is x-2y+4=0, find the equation of QR
- A. x-2y+1=0
- B. 2y+x-3=0
- C. x-2y-3=0
- D. 2x+y-1=0Correct
Explanation
The gradient of PQ is 1/2, so QR's gradient is -2. Using point (1,-1): y+1=-2(x-1), giving y=-2x+1, i.e. 2x+y-1=0.
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