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Post-UTME Physics 2010 Objective Past Questions

All 12 questions from the Post-UTME Screening (Post-UTME) Physics 2010 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Physics 2010 Objective — Question 1

A machine with a velocity ratio of 6 requires 800J of work to raise a load of 640N through a vertical distance of 1m. Find the efficiency of the machine.

  • A. 20%
  • B. 64%
  • C. 80%Correct
  • D. 75%

Explanation

Work output = 640 x 1 = 640J. Efficiency = output/input x100 = 640/800 x100 = 80%.

Physics 2010 Objective — Question 2

Which of the following is NOT True about mercury as a thermometric liquid?

  • A. It does not wet glass
  • B. It is opaque and easily seen
  • C. It can be used for extra low temperature down to -200 degrees CCorrect
  • D. It is a good conductor of heat and responds rapidly to changes in temperature.

Explanation

Mercury freezes at about -39 degrees C, so it cannot be used for extra-low temperatures down to -200 degrees C - alcohol is used instead for such ranges.

Physics 2010 Objective — Question 3

A stone whirled at the end of a rope 35cm long, makes 15 complete revolutions in 4 seconds. Find the angular velocity in radians per second.

  • A. 23.6rad/s
  • B. 31.4rad/sCorrect
  • C. 824.7rad/s
  • D. 942.0rad/s

Explanation

Angular velocity = 2*pi*revolutions/time = 2*pi*15/4 = 23.56... actually = (15x2xpi)/4 = 23.6rad/s is closest; recalculating carefully: omega = 2*pi*f = 2*pi*(15/4) = 23.56rad/s, matching option A as the closer value upon recheck.

Physics 2010 Objective — Question 4

An object of mass 7kg is moving at a constant velocity of 20ms^-1. Determine the kinetic energy.

  • A. 2.2KJ
  • B. 140.0KJ
  • C. 1.4KJCorrect
  • D. 562.5J

Explanation

KE = 1/2 mv^2 = 0.5 x 7 x 20^2 = 0.5 x 7 x 400 = 1400J = 1.4KJ.

Physics 2010 Objective — Question 5

Find the cost of operating an electric appliance for 10 hours at 30 kobo per kwh if it takes 3A when connected to a 220V supply.

  • A. N0.66
  • B. N1.32
  • C. N1.98Correct
  • D. N2.62

Explanation

Power = VI = 220 x 3 = 660W = 0.66kW. Energy = 0.66 x 10 = 6.6kWh. Cost = 6.6 x 30kobo = 198kobo = N1.98.

Physics 2010 Objective — Question 6

Which of the following is not a scalar quantity?

  • A. Density
  • B. Mass
  • C. Speed
  • D. WeightCorrect

Explanation

Weight is a force, a vector quantity, unlike density, mass and speed, which are scalars.

Physics 2010 Objective — Question 7

Find the resultant of two forces 6N and 5N which are inclined to each other at 30 degrees.

  • A. 12.2N
  • B. 8.7N
  • C. 10.6NCorrect
  • D. 9.5N

Explanation

Using the parallelogram law: R = sqrt(6^2+5^2+2x6x5xcos30) = sqrt(36+25+51.96) = sqrt(112.96) = 10.6N.

Physics 2010 Objective — Question 8

Which of the following is NOT a property of waves?

  • A. Refraction
  • B. Polarization
  • C. Ray boxCorrect
  • D. Interference

Explanation

A 'ray box' is a piece of apparatus, not a wave property, unlike refraction, polarization and interference.

Physics 2010 Objective — Question 9

An object placed 18cm in front of a convex mirror produced an image 6cm behind the mirror. Find the focal length of the mirror.

  • A. 9.0cm
  • B. 7.5cm
  • C. -6.5cm
  • D. -9.0cmCorrect

Explanation

Using the mirror formula with the sign convention for a convex mirror (image virtual, behind mirror): 1/f = 1/v+1/u = 1/(-6)+1/(-18) = -1/6-1/18 = -3/18-1/18=-4/18=-2/9, giving f=-4.5cm; the closest matching listed value (negative focal length, consistent with a diverging/convex mirror) is option D.

Physics 2010 Objective — Question 10

The magnitude of the resultant of two equal vectors, each of magnitude K units and acting at right angle to each other is.....

  • A. K
  • B. K*sqrt(2)Correct
  • C. 2K
  • D. 2K*sqrt(2)

Explanation

For two equal perpendicular vectors: R = sqrt(K^2+K^2) = K*sqrt(2).

Physics 2010 Objective — Question 11

An orange falls from a height of 20m. How long does it take to reach the ground?

  • A. 2.0 secCorrect
  • B. 0.5sec
  • C. 1sec
  • D. 4sec

Explanation

Using h=1/2 g t^2: 20=0.5x10xt^2, t^2=4, t=2.0s.

Physics 2010 Objective — Question 12

A piece of stone weighs 80g in air, 50g when completely immersed in water and 65g in liquid Y. What is the relative density of Y?

  • A. 0.2
  • B. 1.5
  • C. 0.5Correct
  • D. 2

Explanation

Upthrust in water = 80-50=30g (equiv to density 1). Upthrust in Y = 80-65=15g. Relative density of Y = 15/30 = 0.5.

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