WAEC Chemistry 2014 Objective — Question 29
Question 29 of 50 from the West African Examinations Council (WAEC) Chemistry 2014 Objective paper, with the correct answer and a full explanation.
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Na₂CO₃(aq) + 2HCl(aq) → 2NaCl(aq)+H₂O(l)+CO₂(g). What volume of 0.02 moldm⁻³ Na₂CO₃(aq) would be required to completely neutralize 40 cm³ of 0.10 moldm⁻³ HCl(aq)?
- A. 200 cm³
- B. 100 cm³Correct
- C. 40 cm³
- D. 20 cm³
Explanation
Using CaVa/na = CbVb/nb with Ca=0.10, Va=40, Cb=0.02, na=2, nb=1: (0.10×40)/2 = (0.02×Vb)/1, so 0.04Vb=4, Vb=100cm³.
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