WAEC Chemistry 2015 Theory — Question 12
Question 12 of 49 from the West African Examinations Council (WAEC) Chemistry 2015 Theory paper, with the correct answer and a full explanation.
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2(a)(i). 'J' is a halogen. If the atomic number of J is quoted as q, using this, the electronic structure of J will be 2,7 (outer shell has seven electrons). Identify the group to which element 'J' belongs, and identify a second element 'Y', a transition element, showing paramagnetism, from the same period. Also identify 'X', an element in group 1, period 4, whose outermost shell contains one electron.
Model answer
'J' belongs to group VII (halogens) since it has 7 electrons in its outer shell. 'Y' is a transition element (period 4) which shows paramagnetism due to unpaired d-electrons. 'X' is an element in group 1 (period 4) with just one electron in its outermost shell, so 'X' loses an electron to 'J' to form an ionic bond, and both attain octet/stable structures - the compound formed between X and R (another element) is X₂R (electrovalent/ionic bond).
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