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WAEC Chemistry 2015 Theory Past Questions

All 49 questions from the West African Examinations Council (WAEC) Chemistry 2015 Theory paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Chemistry 2015 Theory — Question 1

1(a). Define esterification.

Model answer

Esterification is the reaction between an alkanol (alcohol) and an alkanoic acid (carboxylic acid) to give an alkanoate (ester) and water, in the presence of a mineral acid catalyst: ROH + R'COOH ⇌ R'COOR + H₂O. For example, ethanol (C₂H₅OH) reacts with ethanoic acid (CH₃COOH) to yield ethylethanoate (CH₃COOC₂H₅) and water.

Chemistry 2015 Theory — Question 2

1(b). State two properties of plastic.

Model answer

(i) It is a poor conductor of heat and electricity. (ii) It is resistant to corrosion. (Also acceptable: it can be moulded into different shapes; it can be recycled.)

Chemistry 2015 Theory — Question 3

1(c). Name the components of duralumin.

Model answer

The components of duralumin are: Aluminium (Al), Manganese (Mn), Copper (Cu) and Magnesium (Mg).

Chemistry 2015 Theory — Question 4

1(d). What is meant by each of the following terms: (i) Raw material; (ii) Primary product?

Model answer

(i) A raw material simply refers to a starting material employed in producing/manufacturing a substance. (ii) A primary product is a product that can still be converted to another product.

Chemistry 2015 Theory — Question 5

1(e). State Charles' law.

Model answer

Charles' law states that the volume of a given mass of a gas is directly proportional to its absolute temperature, provided the pressure is kept constant.

Chemistry 2015 Theory — Question 6

1(f). List four pieces of protective equipment used in the laboratory.

Model answer

(i) Hand gloves; (ii) Fire extinguisher; (iii) Nose cover (face mask); (iv) Laboratory coat.

Chemistry 2015 Theory — Question 9

1(h)(ii). Name the products formed from the reaction between ethanol and sodium metal.

Model answer

When sodium metal reacts with ethanol, sodium ethoxide and hydrogen gas are produced: C₂H₅OH + Na → C₂H₅ONa + ½H₂.

Chemistry 2015 Theory — Question 11

1(j). Write the IUPAC name for each of the following compounds: (i) NaClO₃; (ii) CuSO₄.5H₂O.

Model answer

(i) NaClO₃ is sodium trioxochlorate (V). (ii) CuSO₄.5H₂O is copper (II) tetraoxosulphate (VI) pentahydrate.

Chemistry 2015 Theory — Question 12

2(a)(i). 'J' is a halogen. If the atomic number of J is quoted as q, using this, the electronic structure of J will be 2,7 (outer shell has seven electrons). Identify the group to which element 'J' belongs, and identify a second element 'Y', a transition element, showing paramagnetism, from the same period. Also identify 'X', an element in group 1, period 4, whose outermost shell contains one electron.

Model answer

'J' belongs to group VII (halogens) since it has 7 electrons in its outer shell. 'Y' is a transition element (period 4) which shows paramagnetism due to unpaired d-electrons. 'X' is an element in group 1 (period 4) with just one electron in its outermost shell, so 'X' loses an electron to 'J' to form an ionic bond, and both attain octet/stable structures - the compound formed between X and R (another element) is X₂R (electrovalent/ionic bond).

Chemistry 2015 Theory — Question 13

2(a)(ii). What type of bond would exist between J and X when they combine?

Model answer

An electrovalent (ionic) bond would exist between J (a halogen, group VII) and X (an alkali metal, group I), since X loses an electron to J to form oppositely charged ions that attract each other.

Chemistry 2015 Theory — Question 14

2(a)(iii). How many neutrons are there in Q? (Consider the table: Element J, O, R, X, Y with given Atomic and Mass numbers.)

Diagram for question 14

Model answer

Number of neutrons = Mass number − Atomic number. Using the atomic and mass numbers given for the relevant element in the table, the neutron number is calculated as mass number minus atomic number.

Chemistry 2015 Theory — Question 15

2(a)(iv). Write the formula of the compound formed when R combines with X.

Model answer

Using the group/valency of R and X (as deduced from their electronic configurations in the table), the formula of the compound formed is derived by cross-balancing their combining powers/valencies, e.g. X₂R or XR depending on their respective valencies.

Chemistry 2015 Theory — Question 16

2(a)(v). State the element which exists as diatomic molecule.

Model answer

The element that exists as a diatomic molecule among those listed is the halogen-type element (e.g. J), since halogens exist as diatomic molecules (e.g. Cl₂, Br₂).

Chemistry 2015 Theory — Question 17

2(a)(vi). Select the element which would belong to the d-block of the periodic table.

Model answer

The transition element (Y) identified in the table, which shows paramagnetism due to partially-filled d-orbitals, belongs to the d-block of the periodic table.

Chemistry 2015 Theory — Question 18

2(b)(i). Explain briefly the term atomic orbital.

Model answer

An atomic orbital simply refers to the region around the nucleus of an atom where there is a high probability/chance of finding an electron.

Chemistry 2015 Theory — Question 19

2(b)(ii). State three postulates of Dalton's atomic theory. List two limitations of this theory in the study of the atom.

Model answer

Postulates of Dalton's atomic theory: (I) An atom is the indivisible part of an element. (II) An atom can neither be created nor destroyed. (III) Atoms of the same element are alike in every aspect and differ from atoms of other elements. Limitations: (I) An atom can still be divided into three sub-atomic particles (protons, neutrons and electrons). (II) Atoms of the same element may not be exactly identical (the concept of isotopy illustrates this).

Chemistry 2015 Theory — Question 20

2(b)(iii). Describe briefly the structure of sodium chloride in its solid state.

Model answer

In the solid form, sodium chloride has a face-centred cubic structure, made up of alternating Na⁺ and Cl⁻ ions held together by strong electrostatic (ionic) forces of attraction in a regular lattice arrangement.

Chemistry 2015 Theory — Question 21

2(c)(i). A sample of carbon is burnt at a rate of 0.50 g per second for 30 minutes to generate heat. Write a balanced equation for the reaction.

Model answer

C(s) + O₂(g) → CO₂(g)

Chemistry 2015 Theory — Question 22

2(c)(ii). Determine the volume of carbon (IV) oxide produced at s.t.p, and the moles of oxygen used up in the process at s.t.p. [C=12.0, O=16.0, Molar volume Vm=22.4 dm³]

Model answer

Time = 30 × 60 = 1800 s. Mass of carbon burnt = 0.50 g/s × 1800 s = 900 g. Moles of carbon = 900/12 = 75 mol. From the equation, 1 mole of carbon produces 1 mole of CO₂ and uses 1 mole of O₂, so moles of CO₂ produced = 75 mol, and moles of O₂ used = 75 mol. Volume of CO₂ at s.t.p = 75 × 22.4 dm³ = 1680 dm³.

Chemistry 2015 Theory — Question 23

3(a)(i). Give three characteristics of homologous series.

Model answer

(i) All members have the same general/functional formula. (ii) All members have a general chemical/molecular formula. (iii) Successive/consecutive members differ by a CH₂ group in their molecular formula and by 14 in their relative molecular mass.

Chemistry 2015 Theory — Question 24

3(a)(ii). Name two groups of compounds which form such a series (homologous series).

Model answer

Examples include: Alkanes, Alkenes, Alkynes, Alkanoic acids, Alkanoates (esters), and Alkanols.

Chemistry 2015 Theory — Question 25

3(b). A saturated organic compound A containing two carbon atoms reacted with ethanoic acid in the presence of a mineral acid to form a compound B with a sweet smell. (i) Name the functional group present in A. (ii) Draw the structure of A. (iii) Write a chemical equation to show the formation of B. (iv) Name the compound B.

Model answer

(i) The functional group present in A is the hydroxyl group (–OH), since A is an alkanol (ethanol) that reacts with an acid to form a sweet-smelling ester. (ii) The structure of A (ethanol, C₂H₅OH) is: H–C(H)(H)–C(H)(H)–OH (i.e. CH₃CH₂OH). (iii) CH₃CH₂OH(l) + CH₃COOH(l) → CH₃COOCH₂CH₃(l) + H₂O(l). (iv) Compound B is ethylethanoate (an ester with a sweet smell).

Chemistry 2015 Theory — Question 26

3(c)(i). Write a balanced equation for the reaction between ethyne and excess bromine.

Model answer

C₂H₂ + 2Br₂ → C₂H₂Br₄ (since ethyne is present in excess bromine, only one mole of ethyne is needed to fully react with the bromine, giving the tetrabromo product).

Chemistry 2015 Theory — Question 27

3(c)(ii). Give the IUPAC name of the product of the reaction in 2(c)(i).

Model answer

The IUPAC name of the product (C₂H₂Br₄) is 1,1,2,2-tetrabromoethane.

Chemistry 2015 Theory — Question 29

3(d)(i). Outline the preparation of ethanol from starch.

Model answer

The starchy material is first ground and hot water is added to liberate the starch; the temperature is maintained around 57.5°C. Malt (partially germinated barley), which contains the enzyme diastase, is added, converting the starch to maltose. The temperature is then lowered to around 20°C and yeast is added; the enzyme maltase in the yeast converts maltose to glucose (via hydrolysis), and the enzyme zymase converts the glucose to ethanol, carbon (IV) oxide, and energy.

Chemistry 2015 Theory — Question 31

3(d)(iii). Give a reason why starch does not reduce Fehling's solution.

Model answer

Starch cannot reduce Fehling's solution because it has no free/oxidizable aldehyde (–CHO) group, unlike reducing sugars such as glucose.

Chemistry 2015 Theory — Question 32

3(d)(iv). Describe briefly a chemical test to confirm the presence of starch.

Model answer

A few drops of iodine solution should be added to the suspected material. If a dark-blue (blue-black) coloration appears, starch is present.

Chemistry 2015 Theory — Question 34

4(b). Aluminium can be prepared commercially by the application of electrolysis. (i) Name the electrolyte used in the process; the ore from which the electrolyte is obtained; and the electrodes used in the electrolysis. (ii) Give two reasons why cryolite, Na₃AlF₆, is added to the electrolyte.

Model answer

(i) Electrolyte used: molten alumina (Al₂O₃) dissolved in molten cryolite. Ore: Bauxite. Electrodes: graphite (carbon) is used as both the anode and the cathode. (ii) Cryolite serves as a solvent for the alumina, and it reduces the melting point of the alumina, making the electrolysis more energy-efficient.

Chemistry 2015 Theory — Question 37

4(c)(iii). Give a reason for your answer in 4(c)(ii).

Model answer

Water gas contains carbon monoxide and hydrogen, both of which are combustible, while producer gas contains carbon monoxide and nitrogen, with nitrogen being non-combustible. This means the entirety of water gas will burn, while only a part of producer gas (the CO portion) will contribute to burning.

Chemistry 2015 Theory — Question 38

4(c)(iv). Write a balanced equation for the production of each gaseous fuel.

Model answer

For water gas: C(s) + H₂O(g) → CO(g) + H₂(g). For producer gas: 2C(s) + O₂(g) + 4N₂(g) → 2CO(g) + 4N₂(g) (i.e. air is passed over hot coke, giving a mixture of CO and unreacted N₂).

Chemistry 2015 Theory — Question 39

4(d)(i). For each of the following reactions, state what would be observed: I. chlorine gas is bubbled through aqueous sodium iodide; II. chlorine gas passed over heated iron in a hard glass tube; III. aqueous silver trioxonitrate (V) is added to aqueous sodium bromide.

Model answer

I. When chlorine gas is bubbled through aqueous sodium iodide, the solution turns reddish-brown (iodine is displaced). II. When chlorine gas is passed over heated iron, a brownish solid (iron (III) chloride, FeCl₃) is formed. III. When aqueous silver trioxonitrate (V) is added to aqueous sodium bromide, a pale (cream) precipitate of silver bromide is observed.

Chemistry 2015 Theory — Question 40

4(d)(ii). Write a balanced chemical equation for each of the reactions in 4(d)(i).

Model answer

I. Cl₂(g) + 2NaI(aq) → 2NaCl(aq) + I₂(aq). II. 2Fe(s) + 3Cl₂(g) → 2FeCl₃(s). III. AgNO₃(aq) + NaBr(aq) → AgBr(s) + NaNO₃(aq).

Chemistry 2015 Theory — Question 43

5(b)(i). Define each of the following terms: I. solubility; II. saturated solution.

Model answer

I. Solubility is defined as the amount (mass) of a given solute that is required to saturate 1 dm³ of a solvent at a particular temperature. II. A saturated solution is one which contains the maximum amount of solute that it can hold at that particular temperature in the presence of undissolved solute.

Chemistry 2015 Theory — Question 45

5(b)(iii). A salt Z of mass 10.2 g was dissolved in 15.4cm³ of distilled water at 40°C. Calculate the solubility of Z in mol/dm³ at 40°C. [MM (Z) = 331]

Model answer

Moles of Z = mass/molar mass = 10.2/331 = 0.0308 mol. Volume = 15.4 cm³ = 0.0154 dm³. If 0.0308 mol is present in 0.0154 dm³, then 1 dm³ would hold (0.0308/0.0154) = 2 mol. Thus, the solubility of Z at 40°C is 2 mol/dm³.

Chemistry 2015 Theory — Question 46

5(c)(i). Town water that has passed through iron pipes contains P and Q ions. In the presence of air, P ions are slowly converted to Q ions. I. Identify P and Q ions. II. Write a balanced equation for the reaction between P ions, hydrogen ions and oxygen to give Q ions and water.

Model answer

I. P ions are Fe²⁺ (iron(II)) ions, while Q ions are Fe³⁺ (iron(III)) ions. II. 4Fe²⁺(aq) + O₂(g) + 4H⁺(aq) → 4Fe³⁺(aq) + 2H₂O(l).

Chemistry 2015 Theory — Question 47

5(c)(ii). Explain briefly a test to confirm the purity of water.

Model answer

The water should be boiled, and the boiling point should be noted using a thermometer. If it boils at exactly 100°C, the water sample is pure; if otherwise (boiling point differs from 100°C), it is impure.

Chemistry 2015 Theory — Question 48

5(c)(iii). State the effect of: I. boiling a temporary hard water; II. adding sodium trioxocarbonate (IV) crystals to permanent hard water.

Model answer

I. Boiling temporary hard water removes the (temporary) hardness, since it decomposes the dissolved calcium/magnesium hydrogen carbonate into insoluble carbonate, which precipitates out: Ca(HCO₃)₂ →(Δ) CaCO₃(s) + H₂O(l) + CO₂(g). II. Adding sodium trioxocarbonate (IV) (washing soda) to permanent hard water removes the permanent hardness by precipitating out the calcium/magnesium ions as insoluble carbonates.

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