Question

2(c)(ii). Determine the volume of carbon (IV) oxide produced at s.t.p, and the moles of oxygen used up in the process at s.t.p. [C=12.0, O=16.0, Molar volume Vm=22.4 dm³]

Accepted Answer

Time = 30 × 60 = 1800 s. Mass of carbon burnt = 0.50 g/s × 1800 s = 900 g.
Moles of carbon = 900/12 = 75 mol.
From the equation, 1 mole of carbon produces 1 mole of CO₂ and uses 1 mole of O₂, so moles of CO₂ produced = 75 mol, and moles of O₂ used = 75 mol.
Volume of CO₂ at s.t.p = 75 × 22.4 dm³ = 1680 dm³.

WAEC Chemistry 2015 Theory — Question 22

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