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WAEC Further Mathematics 2025 Objective — Question 11

Question 11 of 40 from the West African Examinations Council (WAEC) Further Mathematics 2025 Objective paper, with the correct answer and a full explanation.

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Given that 11, p, q, r, s, t, 29 are consecutive terms of a linear sequence (A.P.), find the value of (p+q+r+s+t).

  • A. 180
  • B. 140
  • C. 120
  • D. 100Correct

Explanation

There are 7 terms with a=11 and last term 29. Sum S7 = 7/2(11+29)=140. Since 11+p+q+r+s+t+29=140, p+q+r+s+t = 140-40 = 100.

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