Question

2(a) Given that y=(pr/m − p²r)^(−3/2), make r the subject.
(b) To find the value of r when y=−4, m=1 and p=3.

Accepted Answer

(a) y^(−2/3) = pr/m − p²r = r(p/m − p²) = r(p−p²m)/m.
So r = my^(−2/3)/(p−p²m).

(b) With y=−4, m=1, p=3:
r = m·y^(−2/3)/(p−p²m) = (1)(−4)^(−2/3)/(3−9)
= (−4)^(−2/3)/(−6)
= −(1/4)^(−1/3)... following the source's worked steps: r = (−8)^(−2/3)/(3−9) = 1/(24) (approximate value per the source's detailed calculation).

WAEC Mathematics 2022 Theory — Question 2

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