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WAEC Mathematics 2024 Objective Past Questions

All 50 questions from the West African Examinations Council (WAEC) Mathematics 2024 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Mathematics 2024 Objective — Question 1

1. Multiply 3.4×10⁻⁵ by 7.1×10⁸ and leave the answer in standard form.

  • A. 2.414×10²
  • B. 2.414×10³
  • C. 2.414×10⁴Correct
  • D. 2.414×10⁵

Explanation

3.4×7.1 = 24.14; 10⁻⁵×10⁸ = 10³; 24.14×10³ = 2.414×10⁴.

Mathematics 2024 Objective — Question 2

2. Given that P = {p : 1 < p < 20}, where p is an integer and R = {r : 0 ≤ r ≤ 25, where r is a multiple of 4}, find P∩R.

  • A. {4, 8, 10, 16, 20}
  • B. {4, 8, 12, 16}Correct
  • C. {4, 8, 12, 16, 20}
  • D. {4, 8, 12, 16, 20, 24}

Explanation

P = {2,3,...,19}; R = {0,4,8,12,16,20,24}; P∩R = {4, 8, 12, 16}.

Mathematics 2024 Objective — Question 3

3. The first term of an Arithmetic Progression (A.P) is 2 and the last term is 29. If the common difference is 3, how many terms are in the A.P?

  • A. 8
  • B. 9
  • C. 10Correct
  • D. 11

Explanation

Tn = a + (n-1)d → 29 = 2 + (n-1)3 → n = 10.

Mathematics 2024 Objective — Question 4

4. Express in index form: logₐˣ + logₐʸ = 3

  • A. x + y = 3
  • B. xy = 3
  • C. x + y = a³
  • D. xy = a³Correct

Explanation

logₐ(xy) = 3 ⇒ xy = a³ (since logₙᵖ = m ⇒ P = nᵐ).

Mathematics 2024 Objective — Question 5

5. Simplify: (2p - q)² - (p + q)²

  • A. 3p(p - 2q)Correct
  • B. 2p(p - 3q)
  • C. 3p(2p - q)
  • D. 2p(3p - q)

Explanation

Expand: 4p²-4pq+q² - (p²+2pq+q²) = 3p²-6pq = 3p(p-2q).

Mathematics 2024 Objective — Question 7

7. Find the time for which $1,250.00 will amount to $2,031.25 at 12.5% per annum simple interest.

  • A. 2 years
  • B. 3 years
  • C. 4 years
  • D. 5 yearsCorrect

Explanation

I = 2031.25-1250 = 781.25; t = I×100/(P×R) = 781.25×100/(1250×12.5) = 5 years.

Mathematics 2024 Objective — Question 9

9. The population of a town increases by 3% every year. In the year 2000, the population was 3,000. Find the population in the year 2003.

  • A. 3,182
  • B. 3,278Correct
  • C. 6,591
  • D. 7,515

Explanation

Pₙ = P₀(1+r/100)ⁿ = 3000(1.03)³ ≈ 3,278.

Mathematics 2024 Objective — Question 10

10. A trader gave a change of $540.00 instead of $570.00 to a customer. Calculate the percentage error.

  • A. 5 5/19 %Correct
  • B. 5 5/9 %
  • C. 5 7/19 %
  • D. 5 7/9 %

Explanation

Error = 570-540 = 30; %error = 30/570 × 100% = 5 5/19%.

Mathematics 2024 Objective — Question 11

11. An interior angle of a regular polygon is 168°. Find the number of sides of the polygon.

  • A. 30Correct
  • B. 24
  • C. 15
  • D. 12

Explanation

Exterior angle = 180-168 = 12°; n = 360/12 = 30.

Mathematics 2024 Objective — Question 13

13. A variable W varies partly as M and partly inversely as P. Which of the following correctly represents the relation with k₁ and k₂ constants?

  • A. W = k₁M / k₂P
  • B. W = (k₁+k₂)M / P
  • C. W = k₁M + k₂/PCorrect
  • D. W = (k₁+k₂)M + P

Explanation

W ∝ M and W ∝ 1/P combine (partial variation) to give W = k₁M + k₂/P.

Mathematics 2024 Objective — Question 14

14. A cylindrical metallic barrel of height 2.5 m and radius 0.245 m is closed at one end. Find, correct to one decimal place, the total surface area of the barrel. [Take π = 22/7]

  • A. 2.1 m²
  • B. 3.5 m²
  • C. 4.0 m²Correct
  • D. 9.4 m²

Explanation

TSA = πr(2h+r) = (22/7)(0.245)[2(2.5)+0.245] ≈ 4.0 m² (1 d.p.).

Mathematics 2024 Objective — Question 15

15. Make R the subject of the relation V = πl(R² - r²).

  • A. R = √(V/πl + r²)Correct
  • B. R = √(V/πl - r²)
  • C. R = √(V - πlr²)
  • D. R = √(V + πlr²)

Explanation

R² = V/πl + r² ⇒ R = √(V/πl + r²).

Mathematics 2024 Objective — Question 16

16. Consider the following statements: m: Edna is respectful; n: Edna is brilliant. If m ⟹ n, which of the following is valid?

  • A. ~m ⟹ ~n
  • B. n ⟹ ~m
  • C. ~n ⟹ ~mCorrect
  • D. n ⟹ m

Explanation

The contrapositive of m⟹n is ~n⟹~m, and a statement is always logically equivalent (valid) to its contrapositive.

Mathematics 2024 Objective — Question 17

17. A number is added to both the numerator and the denominator of the fraction 1/8. If the result is 1/2, find the number.

  • A. 3
  • B. 4
  • C. 5
  • D. 6Correct

Explanation

(1+x)/(8+x) = 1/2 → 2(1+x) = 8+x → x = 6.

Mathematics 2024 Objective — Question 18

18. Gifty, Justina and Frank shared 60 oranges in the ratio 5 : 3 : 7 respectively. How many oranges did Justina receive?

  • A. 12Correct
  • B. 16
  • C. 20
  • D. 28

Explanation

Total ratio = 15; Justina's share = (3/15) × 60 = 12.

Mathematics 2024 Objective — Question 19

19. Find the quadratic equation whose roots are 2/3 and -1.

  • A. 3x² + x - 2 = 0Correct
  • B. 3x² - x - 2 = 0
  • C. 3x² + x + 2 = 0
  • D. 3x² + x - 1 = 0

Explanation

Sum of roots = -1/3, product = -2/3; x² + (1/3)x - 2/3 = 0 → 3x² + x - 2 = 0.

Mathematics 2024 Objective — Question 20

20. A piece of rod of length 44 m is cut to form a rectangular shape such that the ratio of the length to the breadth is 7 : 4. Find the breadth.

  • A. 8 mCorrect
  • B. 14 m
  • C. 16 m
  • D. 24 m

Explanation

Perimeter = 2(L+B) = 44 → L+B = 22; L:B = 7:4 → B = 8 m.

Mathematics 2024 Objective — Question 21

21. In the diagram, MN∥KL, ML and KN intersect at X. |MN| = 12 cm, |MX| = 10 cm and |KL| = 9 cm. If the area of ΔMXN is 16 cm², calculate the area of ΔLXK.

Diagram for question 21
  • A. 8 cm²
  • B. 9 cm²Correct
  • C. 10 cm²
  • D. 12 cm²

Explanation

ΔMXN and ΔLXK are similar; ratio of areas = (KL/MN)² = (9/12)². Area LXK = 16×81/144 = 9 cm².

Mathematics 2024 Objective — Question 22

22. A ladder 15 m long leans against a vertical pole, making an angle of 72° with the horizontal. Calculate, correct to one decimal place, the distance between the foot of the ladder and the pole.

  • A. 15.8 m
  • B. 14.3 m
  • C. 4.9 m
  • D. 4.6 mCorrect

Explanation

d = 15cos72° ≈ 4.6 m.

Mathematics 2024 Objective — Question 23

23. In the diagram, O is the centre of the circle. If |OA| = 25 cm and |AB| = 40 cm, find |OH|.

Diagram for question 23
  • A. 15 cmCorrect
  • B. 20 cm
  • C. 25 cm
  • D. 30 cm

Explanation

OH bisects AB, so AH = 20 cm. By Pythagoras: OH² = 25²-20² = 225 → OH = 15 cm.

Mathematics 2024 Objective — Question 25

25. A car valued at $600,000.00 depreciates by 10% each year. What will be the value of the car at the end of two years?

  • A. $120,000.00
  • B. $480,000.00
  • C. $486,000.00Correct
  • D. $540,000.00

Explanation

Value = $600,000 × (0.9)² = $486,000.

Mathematics 2024 Objective — Question 26

26. The length and breadth of a cuboid are 15 cm and 8 cm respectively. If the volume of the cuboid is 1,560 cm³, calculate the total surface area.

  • A. 976 cm²
  • B. 383 cm²Correct
  • C. 792 cm²
  • D. 746 cm²

Explanation

H = 1560/(15×8) = 13 cm; TSA = 2(LB+BH+LH) = 2(120+104+195).

Mathematics 2024 Objective — Question 27

27. The number 1621 was subtracted from 6244 in base x. If the result was 4323, find x.

  • A. SevenCorrect
  • B. Eight
  • C. Nine
  • D. Ten

Explanation

Converting to base 10 and solving gives x² - 7x = 0, so x = 7 (base seven).

Mathematics 2024 Objective — Question 28

28. Factorize completely: 27x² - 48y²

  • A. 3(3x + 4y)(3x + 4y)
  • B. 3(3x + 4y)(3x - 4y)Correct
  • C. 3(9x - 16y)(9x + 16y)
  • D. 3(9x - 16y)(9x - 16y)

Explanation

27x²-48y² = 3(9x²-16y²) = 3(3x+4y)(3x-4y).

Mathematics 2024 Objective — Question 29

29. For what values of x is (x-3)/4 + (x+1)/8 ≥ 2 ?

  • A. x ≥ 5
  • B. x ≥ 6
  • C. x ≥ 7Correct
  • D. x ≥ 8

Explanation

Multiply through by 8: 2(x-3)+(x+1) ≥ 16 → 3x-5 ≥ 16 → x ≥ 7.

Mathematics 2024 Objective — Question 30

30. In the diagram, ∠SQR = 52° and ∠PRT = 16°. Find the value of the angle marked y.

Diagram for question 30
  • A. 64°
  • B. 68°
  • C. 112°Correct
  • D. 128°

Explanation

y is the exterior angle of cyclic quadrilateral RQST; y = 52°+16°+... = 112°.

Mathematics 2024 Objective — Question 31

31. In the diagram, JKL is a tangent to the circle GHIK at K. ∠LKG = 38° and ∠KHG = 87°. Calculate the value of the angle marked x.

Diagram for question 31
  • A. 93°
  • B. 55°Correct
  • C. 42°
  • D. 23°

Explanation

KĜL = 87° (exterior angle of cyclic quadrilateral); in ΔKGL: 87°+x+38° = 180° → x = 55°.

Mathematics 2024 Objective — Question 32

32. A cone and a cylinder are of equal volume. The base radius of the cone is twice the radius of the cylinder. What is the ratio of the height of the cylinder to that of the cone?

  • A. 5 : 4
  • B. 4 : 3Correct
  • C. 2 : 1
  • D. 3 : 4

Explanation

Equal volumes with R_cone = 2r_cyl gives h_cyl : h_cone = 4 : 3.

Mathematics 2024 Objective — Question 33

33. Find, correct to the nearest whole number, the value of h in the diagram.

Diagram for question 33
  • A. 15 m
  • B. 22 m
  • C. 23 mCorrect
  • D. 18 m

Explanation

Using the given side lengths and Pythagoras' theorem, h ≈ 23 m.

Mathematics 2024 Objective — Question 35

35. In the diagram, PQ∥RS, ∠WYZ = 44° and ∠WXY = 50°. Find ∠WTX.

  • A. 65°
  • B. 68°
  • C. 86°Correct
  • D. 90°

Explanation

∠XWY = ∠ZYW = 44° (alternate angles); in ΔWTX: ∠W+∠T+∠X = 180°, giving ∠WTX = 86°.

Mathematics 2024 Objective — Question 36

36. The perimeter of a rectangular garden is 90 m. If the width is 7 m less than the length, find the length of the garden.

  • A. 19 m
  • B. 23 m
  • C. 24 m
  • D. 26 mCorrect

Explanation

2(L+(L-7)) = 90 → 2L-7 = 45 → L = 26 m.

Mathematics 2024 Objective — Question 37

37. Four of the angles of a hexagon sum up to 420°. If the remaining angles are equal, find the value of each of the angles.

  • A. 60°
  • B. 100°
  • C. 120°
  • D. 150°Correct

Explanation

Sum of interior angles of hexagon = 720°; remaining two = 300°; each = 150°.

Mathematics 2024 Objective — Question 39

39. The following are the masses (in kg) of members in a club: 59, 44, 53, 57, 49, 40, 48 and 50. Calculate the mean mass.

  • A. 40 kg
  • B. 44 kg
  • C. 50 kgCorrect
  • D. 53 kg

Explanation

Mean = (59+44+53+57+49+40+48+50)/8 = 400/8 = 50 kg.

Mathematics 2024 Objective — Question 40

40. Calculate the variance of the distribution of masses: 59, 44, 53, 57, 49, 40, 48 and 50.

  • A. 35Correct
  • B. 36
  • C. 40
  • D. 50

Explanation

Variance S² = Σf(x-x̄)²/Σf = 280/8 = 35.

Mathematics 2024 Objective — Question 41

41. Two opposite sides of a rectangle are (5x+3) m and (2x+9) m. If an adjacent side is (6x-7) m, find, in m², the area of the rectangle.

  • A. 45 m²
  • B. 65 m²Correct
  • C. 125 m²
  • D. 165 m²

Explanation

5x+3 = 2x+9 → x = 2; sides = 13 m and 5 m; Area = 65 m².

Mathematics 2024 Objective — Question 43

43. The area of a sector of a circle with radius 7 cm is 51.3 cm². Calculate, correct to the nearest whole number, the angle of the sector. [Take π = 22/7]

  • A. 60°
  • B. 120°Correct
  • C. 150°
  • D. 180°

Explanation

θ = (51.3×360×7)/(22×7²) ≈ 120°.

Mathematics 2024 Objective — Question 44

44. A cliff on the bank of a river is 87 m high. A boat on the river is 22 m away from the foot of the cliff. Calculate, correct to the nearest degree, the angle of depression of the boat from the top of the cliff.

Diagram for question 44
  • A. 76°Correct
  • B. 64°
  • C. 36°
  • D. 24°

Explanation

tan α = 87/22 = 3.9545; α = tan⁻¹(3.9545) ≈ 76°.

Mathematics 2024 Objective — Question 45

45. In the diagram, TU is a tangent to the circle SPQR at P. If ∠PTS = 44° and ∠SQP = 35°, find ∠PST.

Diagram for question 45
  • A. 101°Correct
  • B. 125°
  • C. 130°
  • D. 135°

Explanation

∠SPT = 35° (angle in alternate segment); in ΔPST: 35°+44°+∠PST = 180° → ∠PST = 101°.

Mathematics 2024 Objective — Question 46

46. The probability that Amaka will pass an examination is 3/7 and that Bala will pass is 4/9. Find the probability that both will pass the examination.

  • A. 2/21
  • B. 4/21Correct
  • C. 5/21
  • D. 9/21

Explanation

P(both) = 3/7 × 4/9 = 12/63 = 4/21.

Mathematics 2024 Objective — Question 48

48. Find the range of the following set of numbers: 28, 29, 39, 38, 33, 37, 26, 20, 15 and 25.

  • A. 22
  • B. 24Correct
  • C. 25
  • D. 27

Explanation

Range = maximum - minimum = 39 - 15 = 24.

Mathematics 2024 Objective — Question 49

49. The fourth and eighth terms of an Arithmetic Progression are 16 and 40 respectively. Find the common difference.

  • A. -6
  • B. 6Correct
  • C. -2
  • D. 2

Explanation

T₄=a+3d=16, T₈=a+7d=40; subtracting: 4d=24 → d=6.

Mathematics 2024 Objective — Question 50

50. For what values of y is (y+2)/(8y² - 10y + 3) not defined?

  • A. -3/4, -1/2
  • B. -3/4, 1/2
  • C. 3/4, -1/2
  • D. 3/4, 1/2Correct

Explanation

Denominator = 0: 8y²-10y+3=0 → (4y-3)(2y-1)=0 → y = 3/4 or 1/2.

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