Question

13(c) A car B moves towards a stationary car A. If B produces an ultrasonic sound at a point and it takes 5.6x10⁻³s for a beep to be heard in B, calculate the distance between the two cars at that instant. (Speed of sound in air = 340 ms⁻¹)

Model answer

v = 2d/t, so d = vt/2. Given speed of sound v = 340 m/s, time t = 5.6x10⁻³s: d = (340 x 5.6x10⁻³)/2 = 0.952 m.

Accepted Answer

v = 2d/t, so d = vt/2. Given speed of sound v = 340 m/s, time t = 5.6x10⁻³s: d = (340 x 5.6x10⁻³)/2 = 0.952 m.

WAEC Physics 2011 Theory — Question 28

Sign up free to unlock