WAEC Physics 2012 Objective — Question 13
Question 13 of 50 from the West African Examinations Council (WAEC) Physics 2012 Objective paper, with the correct answer and a full explanation.
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A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms⁻¹. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor. [g = 10 ms⁻²]
- A. A. 0.75m
- B. B. 2.25 m
- C. C. 8.22 mCorrect
- D. D. 15.00 m
Explanation
Time to fall: H = ½gt² => 1.5 = ½x10xt² => t = 0.55s (approx). Horizontal distance R = u x t = 15 x 0.55 = 8.22 m.
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