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WAEC Physics 2012 Objective — Question 13

Question 13 of 50 from the West African Examinations Council (WAEC) Physics 2012 Objective paper, with the correct answer and a full explanation.

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A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms⁻¹. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor. [g = 10 ms⁻²]

  • A. A. 0.75m
  • B. B. 2.25 m
  • C. C. 8.22 mCorrect
  • D. D. 15.00 m

Explanation

Time to fall: H = ½gt² => 1.5 = ½x10xt² => t = 0.55s (approx). Horizontal distance R = u x t = 15 x 0.55 = 8.22 m.

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