WAEC Physics 2012 Objective — Question 22
Question 22 of 50 from the West African Examinations Council (WAEC) Physics 2012 Objective paper, with the correct answer and a full explanation.
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A metal of mass 200 g at a temperature of 100°C is placed in 100 g of water at 25°C in a container of negligible heat capacity. If the final steady temperature is 30°C, calculate the specific heat capacity of the metal. (Specific heat capacity of water is 4200 Jkg⁻¹K⁻¹)
- A. A. 150 Jkg⁻¹K⁻¹Correct
- B. B. 300 Jkg⁻¹K⁻¹
- C. C. 320 Jkg⁻¹K⁻¹
- D. D. 1960 Jkg⁻¹K⁻¹
Explanation
Heat lost by metal = heat gained by water. 0.2 x Cm x (100-30) = 0.1 x 4200 x (30-25). Cm = (100x4200x5)/(200x70) = 150 Jkg⁻¹K⁻¹.
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