WAEC Physics 2012 Theory — Question 3
Question 3 of 15 from the West African Examinations Council (WAEC) Physics 2012 Theory paper, with the correct answer and a full explanation.
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3. A ray of light is incident on an air-glass boundary at an angle θ. If the angle between the partially reflected ray and the refracted ray is 90°, calculate θ, given that the refractive index of glass is 1.50.
Model answer
Since the reflected ray and refracted ray are perpendicular to each other (90° apart), and using the geometry of reflection/refraction, the angle of incidence θ must satisfy: the angle of refraction r = 90°−θ (since reflected angle = θ, and reflected+refracted+90° arrangement). Using Snell's law: n = sinθ/sin r = sinθ/sin(90°−θ) = sinθ/cosθ = tanθ. Thus, tanθ = 1.50, so θ = tan⁻¹1.50 = 56.3° (this angle is known as Brewster's angle).
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