WAEC Physics 2013 Objective — Question 21
Question 21 of 50 from the West African Examinations Council (WAEC) Physics 2013 Objective paper, with the correct answer and a full explanation.
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Ice of mass 10g at −5°C was completely converted to water at 0°C. Calculate the quantity of heat used. [Specific heat capacity of ice = 2.1Jg⁻¹K⁻¹, specific latent heat of fusion of ice = 336Jg⁻¹]
- A. 3465 JCorrect
- B. 3255 J
- C. 3465 J
- D. 16821 J
Explanation
Heat needed = heat to warm ice from −5°C to 0°C + heat to melt ice at 0°C = mcΔT + mLf = (10×2.1×5) + (10×336) = 105 + 3360 = 3465J.
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