Free account: track your progress — Sign up free

WAEC Physics 2014 Objective — Question 41

Question 41 of 50 from the West African Examinations Council (WAEC) Physics 2014 Objective paper, with the correct answer and a full explanation.

Advertisement

A 15µF capacitor is connected to a 240V, 50Hz a.c. source. Calculate the reactance of the capacitor. [π=3.142]

  • A. 16 Ω
  • B. 68 Ω
  • C. 106 Ω
  • D. 212 ΩCorrect

Explanation

Xc = 1/(2πfC) = 1/(2×3.142×50×15×10⁻⁶) ≈ 212Ω.

Advertisement

Sign up free to unlock

  • Score tracking
  • Practice history
  • Saved questions
  • Progress dashboard
  • Personalized sessions
  • Weak-topic breakdown

…and/or go further with premium services and No Ads.