WAEC Physics 2014 Theory — Question 2
Question 2 of 22 from the West African Examinations Council (WAEC) Physics 2014 Theory paper, with the correct answer and a full explanation.
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2. A tennis ball projected at an angle θ attains a range R=78m. If the velocity imparted to the ball by the racket is 30ms⁻¹, calculate θ. [g=10ms⁻²]
Model answer
R = u²sin2θ/g 78 = 30²sin2θ/10 = 90sin2θ sin2θ = 78/90 = 0.867 2θ = 60.1° (or 119.9°) θ ≈ 30° (or equivalently θ ≈ 60°, the complementary angle giving the same range)
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