WAEC Physics 2014 Theory — Question 22
Question 22 of 22 from the West African Examinations Council (WAEC) Physics 2014 Theory paper, with the correct answer and a full explanation.
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10(d). The surface of an ear drum (assumed circular) has a radius 2.1mm. It resonates with an amplitude of 0.8×10⁻⁷m as a result of impulses received from an external body vibrating at 2,400Hz. If the resulting pressure change on the ear drum is 3.6×10⁻³Nm⁻², calculate the: (i) period of oscillation; (ii) velocity.
Model answer
(i) Period, T = 1/f = 1/2400 ≈ 4.17×10⁻⁴s (ii) Velocity (maximum particle velocity) = amplitude × angular frequency = a×2πf = 0.8×10⁻⁷ × 2π×2400 ≈ 0.8×10⁻⁷ × 15,080 ≈ 1.21×10⁻³ m/s
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