WAEC Physics 2015 Objective — Question 35
Question 35 of 50 from the West African Examinations Council (WAEC) Physics 2015 Objective paper, with the correct answer and a full explanation.
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An alternating current supply is connected to an electric lamp which lights with the same brightness as it does with a direct current source of e.m.f. 6 V. The peak potential difference of the a.c. supply is
- A. 4.6 V
- B. 6.0 V
- C. 8.5 VCorrect
- D. 12.0 V
Explanation
Peak voltage = rms voltage × √2 = 6×1.414 ≈ 8.5 V.
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