WAEC Physics 2015 Objective — Question 46
Question 46 of 50 from the West African Examinations Council (WAEC) Physics 2015 Objective paper, with the correct answer and a full explanation.
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In a nuclear fission process, the mass defect was 1.2×10⁻⁵ kg. Calculate the energy released. [Speed of light in vacuum = 3.0×10⁸ ms⁻¹]
- A. 1.08×10¹¹ J
- B. 5.20×10¹¹ J
- C. 1.08×10¹² JCorrect
- D. 2.50×10¹³ J
Explanation
E = Δmc² = 1.2×10⁻⁵ × (3×10⁸)² = 1.08×10¹² J.
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