WAEC Physics 2015 Objective — Question 8
Question 8 of 50 from the West African Examinations Council (WAEC) Physics 2015 Objective paper, with the correct answer and a full explanation.
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A body is projected with an initial velocity u at an angle θ to the horizontal. The time taken by it to reach its maximum height is given by the expression
- A. 2u sinθ/g
- B. u² sin²θ/2g
- C. u sinθ/gCorrect
- D. u sinθ/2g
Explanation
At maximum height the vertical velocity is zero. Using v = u sinθ − gt with v = 0 gives t = u sinθ/g.
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