WAEC Physics 2016 Objective — Question 26
Question 26 of 50 from the West African Examinations Council (WAEC) Physics 2016 Objective paper, with the correct answer and a full explanation.
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26. The distance between two successive troughs of a wave is 0.4 m. If the frequency of the source is 825 Hz, calculate the speed of the wave. A. 412.5 ms⁻¹ B. 825.0 ms⁻¹ C. 330 ms⁻¹ D. 206.25 ms⁻¹
- A. 412.5 ms⁻¹
- B. 825.0 ms⁻¹
- C. 330 ms⁻¹Correct
- D. 206.25 ms⁻¹
Explanation
Given λ=distance between successive troughs=0.4m, f=825Hz; v=fλ=825×0.4=330 ms⁻¹.
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