Question

37. A man and his friend have masses 70 kg and 60 kg respectively. If they are seated 1.0 m apart, calculate the gravitational force of attraction between them. (G=6.67×10⁻¹¹Nm²kg⁻²) A. 1.59×10⁻⁶N B. 2.80×10⁻⁷N C. 1.30×10⁻²N D. 6.30×10⁻⁹N

A. 1.59×10⁻⁶N
B. 2.80×10⁻⁷NCorrect
C. 1.30×10⁻²N
D. 6.30×10⁻⁹N

Explanation

F=GM₁M₂/r² = 6.67×10⁻¹¹×70×60/1² = 2.8×10⁻⁷N.

Accepted Answer

B. 2.80×10⁻⁷N

Answer

A. 1.59×10⁻⁶N

Answer

C. 1.30×10⁻²N

Answer

D. 6.30×10⁻⁹N

WAEC Physics 2016 Objective — Question 37

Explanation

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