WAEC Physics 2017 Objective — Question 11
Question 11 of 50 from the West African Examinations Council (WAEC) Physics 2017 Objective paper, with the correct answer and a full explanation.
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A simple harmonic oscillator has a period of 0.02 s and amplitude of 0.25 m. Calculate the speed in ms⁻¹ at the centre of the oscillation.
- A. A. 1.25π
- B. B. 100.00π
- C. C. 25.00πCorrect
- D. D. 400.00π
Explanation
Given: Period, T=0.025 (approx 0.02s); Amplitude, A=0.25m; velocity(v)=ωA and ω=2πf where f=1/T=1/0.02=50Hz; thus v=ωA=2πfA=25π m/s.
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