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WAEC Physics 2017 Objective Past Questions

All 50 questions from the West African Examinations Council (WAEC) Physics 2017 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Physics 2017 Objective — Question 1

Which of the following properties of a long steel bar would alter if the bar were melted, recast into a cube and allowed to cool to its original temperature?

  • A. A. Density
  • B. B. Volume
  • C. C. Specific heat capacity
  • D. D. Electrical resistanceCorrect

Explanation

Recasting into a different shape changes the length and cross-sectional area, altering electrical resistance (R=ρl/A), even though density, volume and specific heat capacity remain the same.

Physics 2017 Objective — Question 2

Which of the following instruments is the best for measuring the diameter of a thin constantan wire?

  • A. A. Callipers
  • B. B. Metre rule
  • C. C. Micrometer screw gaugeCorrect
  • D. D. Vernier callipers

Explanation

The micrometer screw gauge is used to measure the diameter of a wire or anything less than that. Its reading accuracy is 0.01mm or 0.001cm. It is more accurate than the Vernier calliper.

Physics 2017 Objective — Question 3

What is the density of a fuel of relative density 0.72? [Density of water = 1000 kgm⁻³]

  • A. A. 72 kgm⁻³
  • B. B. 720 kgm⁻³Correct
  • C. C. 7200 kgm⁻³
  • D. D. 72000 kgm⁻³

Explanation

Relative density (R.D) of fuel = 0.72, density of water = 1000 kgm⁻³. R.D = (density of fuel)/(density of water) = 0.72x1000 = 720 kgm⁻³.

Physics 2017 Objective — Question 4

The types of motion which a cylindrical drum rolling down an inclined plane undergoes are

  • A. A. circular and translational
  • B. B. rotational and translationalCorrect
  • C. C. rotational and circular
  • D. D. rectilinear and circular

Explanation

A cylindrical drum rolling down an inclined plane undergoes both translational (down the incline) and rotational (about its own axis) motion.

Physics 2017 Objective — Question 5

Which of the following statements about a moving particle is correct?

  • A. A. If the resultant force acting on the particle is zero, then it is in dynamic equilibriumCorrect
  • B. B. If the resultant force acting on the particle is greater than zero, it is moving with a uniform velocity
  • C. C. The rate of change of its momentum with time takes place in a direction opposite to that of its motion
  • D. D. The particle falling freely covers equal distances in equal time intervals

Explanation

Given a horizontal surface, if the body has mass m kg, the frictional force (Fr) can be gotten from Fr=μ x R (friction=coeff. of static x normal reaction, where R=mg, opposite the weight of the body). Static friction depends on the weight of body and the nature of the surface, but not on the surface area of contact. When the resultant force acting on a particle is zero, it is in dynamic equilibrium (constant velocity or at rest).

Physics 2017 Objective — Question 6

Which of the following statements about static friction is correct? It

  • A. A. is independent of the nature of surfaces in contact
  • B. B. depends on the area of surfaces in contact
  • C. C. depends on the relative motion between the surfaces in contact
  • D. D. depends on the weight of the moving bodyCorrect

Explanation

Static friction depends on the weight of the body. It also depends on the nature of the surface - a smooth glass surface has a smaller static friction than a rough wooden surface, but it does not depend on the surface area of contact.

Physics 2017 Objective — Question 7

Two cars X and Y travelling in opposite directions along the same highway at uniform velocities 110 kmh⁻¹ and 90 kmh⁻¹ respectively pass each other at a certain point. The velocity of X relative to Y at the time they pass each other is

  • A. A. 200 kmh⁻¹Correct
  • B. B. 100kmh⁻¹
  • C. C. 40kmh⁻¹
  • D. D. 20kmh⁻¹

Explanation

Since they are moving in opposite directions, the relative velocity is a vector quantity given by the sum of both velocities = (110+90)km/hr = 200km/hr.

Physics 2017 Objective — Question 8

The average speed of an object is determined by dividing the sum of its initial and final speeds by two only when the acceleration is

  • A. A. changing
  • B. B. uniformCorrect
  • C. C. increasing
  • D. D. decreasing

Explanation

When the acceleration is uniform, the average speed is determined by directly summing its initial and final speeds by two.

Physics 2017 Objective — Question 9

A body is projected horizontally from the top of a cliff 45m above the ground. If the body lands at a distance 30m from the foot of the cliff, calculate the speed of projection. [g = 10 ms⁻²]

  • A. A. 10 ms⁻¹
  • B. B. 15ms⁻¹
  • C. C. 20ms⁻¹Correct
  • D. D. 30ms⁻¹

Explanation

Given: Height of cliff, H=45m; Range, R=30m; speed of projection=ux (horizontal projection). From s=ut+½gt²: vertical motion gives s=H=½gt²; 45=½x10xt²; t²=(45x2)/10=9, t=3s. Horizontal resolution: s=uxt+½x0xt²; R=uxt; 30=uxx3; ux=10ms⁻¹. (Note: the official answer key states C, 20ms⁻¹; this may reflect a slightly different setup in the original figures.)

Physics 2017 Objective — Question 10

Which of the following statements best describes a rigid body? A body which

  • A. A. is not easily deformedCorrect
  • B. B. when deformed regains its shape
  • C. C. is brittle
  • D. D. when deformed remains deformed

Explanation

A rigid body is one that is not easily deformed.

Physics 2017 Objective — Question 11

A simple harmonic oscillator has a period of 0.02 s and amplitude of 0.25 m. Calculate the speed in ms⁻¹ at the centre of the oscillation.

  • A. A. 1.25π
  • B. B. 100.00π
  • C. C. 25.00πCorrect
  • D. D. 400.00π

Explanation

Given: Period, T=0.025 (approx 0.02s); Amplitude, A=0.25m; velocity(v)=ωA and ω=2πf where f=1/T=1/0.02=50Hz; thus v=ωA=2πfA=25π m/s.

Physics 2017 Objective — Question 12

A vertical string, suspended from a fixed point and having a small mass attached to the free end, is set into oscillations. Which of the following statements about the system are correct? I. The potential energy of the mass is minimum at the middle of the swing. II. Its kinetic energy is maximum at the middle of the swing. III. The sum of the potential and kinetic energies is constant throughout the swing.

  • A. A. I, II and IIICorrect
  • B. B. I and II only
  • C. C. II and III only
  • D. D. I and III only

Explanation

At the middle (equilibrium point) of the swing, PE is minimum and KE is maximum. The total mechanical energy (PE+KE) is constant throughout the motion by conservation of energy - all three statements are correct.

Physics 2017 Objective — Question 13

A moving body of mass 25.0kg undergoes a uniform retardation of 20.0 ms⁻². Calculate the magnitude of the retarding force.

  • A. A. 1.25 N
  • B. B. 8.00 N
  • C. C. 45.00 N
  • D. D. 500.00 NCorrect

Explanation

Magnitude of retarding force = [mass of the moving body] x [retardation] = 25 x 20 = 500N.

Physics 2017 Objective — Question 14

Which of the following sources of energy is/are exhaustible? I. Solar II. Fossil fuels III. Tidal power

  • A. A. II onlyCorrect
  • B. B. III only
  • C. C. I and II only
  • D. D. II and III only

Explanation

Both solar and tidal energy sources are renewable and so are inexhaustible. Fossil fuel is non-renewable and exhaustible.

Physics 2017 Objective — Question 15

A machine is said to be a third class lever when the

  • A. A. load is between the fulcrum and effort
  • B. B. fulcrum is between the effort and load
  • C. C. effort is between the fulcrum and loadCorrect
  • D. D. fulcrum is directly below the load

Explanation

For a third class lever, the effort is between the load and the fulcrum, e.g. sugar tongs, forearm (M.A and V.R are less than 1, i.e. mechanical disadvantage).

Physics 2017 Objective — Question 16

A thermometer records 680 mmHg at steam point and 440 mmHg at ice point. The temperature it records at 380mmHg is

  • A. A. -25°C
  • B. B. -20°CCorrect
  • C. C. 20°C
  • D. D. 25°C

Explanation

Using (100-X)/(100-0) = (680-380)/(680-440): 100-X = ((680-380)x100)/(680-440) = (300x100)/240 = 125; X = 100-125 = -25°C. (Note: the official answer key states B, -20°C.)

Physics 2017 Objective — Question 17

The advantages of the thermoelectric thermometer include the following characteristics except that it

  • A. A. can measure rapidly changing temperatures
  • B. B. can measure high and low temperatures
  • C. C. can measure temperature almost at a point
  • D. D. is fairly sensitiveCorrect

Explanation

The thermoelectric thermometer (thermocouple) is very sensitive and not fairly sensitive - that is why it can measure rapidly changing or momentary temperatures.

Physics 2017 Objective — Question 18

In a thermos flask, heat loss by radiation is minimized by the

  • A. A. silvered surfacesCorrect
  • B. B. vacuum within the double walls
  • C. C. plastic stopper
  • D. D. cork support

Explanation

In a thermos flask, the silvery walls prevent heat loss by radiation. The vacuum between the double walls prevents heat loss by conduction and convection.

Physics 2017 Objective — Question 19

The pressure P, volume V and absolute temperature T of a given mass of an ideal gas change simultaneously. Which of the following equations is correct about the gas?

  • A. A. PV = constant/T
  • B. B. P/T = constant
  • C. C. P/T x 1/T = constant
  • D. D. T/(PV) = constantCorrect

Explanation

If we divide through by PV, we obtain 1/T = constant/PV, which rearranges to give T/(PV) = constant.

Physics 2017 Objective — Question 20

Specific heat capacity of a body means that when 26.4 J heat energy is supplied to a body of

  • A. A. mass 1000 kg the temperature rises by 1K
  • B. B. mass 1 kg, the temperature rises by 1000 K
  • C. C. mass 1 kg, the temperature rises by 1 KCorrect
  • D. D. mass 1000 kg, the temperature rises by 1 K

Explanation

The specific heat capacity of a body is the quantity of heat required to raise/lower the temperature of the unit mass (1 kg) of the body by 1 Kelvin (1 K).

Physics 2017 Objective — Question 21

An electric drill rated 400W is used to drill a hole in copper of mass 400 g in 20 s. Calculate the rise in temperature if all the heat produced is absorbed by the copper. [Specific heat capacity of copper = 400 J kg⁻¹ K⁻¹]

  • A. A. 100°C
  • B. B. 75°C
  • C. C. 50°CCorrect
  • D. D. 45°C

Explanation

Power = 400W, mass of copper = 400g = 0.4kg, time = 20s, rise in temperature = ? Heat absorbed by copper = power x time = 400x20 = 8000J. Heat absorbed = mass x specific heat capacity x ΔT: ΔT = Heat absorbed/(mass x C) = 8000/(0.4x400) = 50°C.

Physics 2017 Objective — Question 22

A solid of mass 0.5kg initially at 50°C melts at 60°C. Calculate the quantity of heat required to melt it completely. [Specific heat capacity of the solid=2.0 KJ kg⁻¹ K⁻¹, Specific latent heat of fusion of solid=1.0KJ kg⁻¹]

  • A. A. 1500J
  • B. B. 10000J
  • C. C. 10500JCorrect
  • D. D. 15000J

Explanation

Given: mass of the solid=0.5kg; initial temperature of solid=50°C; melting point of solid=60°C; specific heat capacity of solid=2000J/kg-K; specific latent heat of fusion of solid=1000J/kg. Heat required to melt the solid completely = (heat required to raise the temperature from 50°C to 60°C) + (heat required to melt the body at 60°C) = mcΔT+ml = (0.5x2000x(60-50)) + (0.5x1000) = 10,000+500 = 10,500J.

Physics 2017 Objective — Question 23

Dew point is not affected by

  • A. A. temperature
  • B. B. wind
  • C. C. the amount of water vapour in the atmosphere
  • D. D. atmospheric pressureCorrect

Explanation

Dew point is affected by temperature, wind, and the amount of water vapour in the atmosphere, but not by atmospheric pressure.

Physics 2017 Objective — Question 24

A certain wave has a speed of 20 ms⁻¹. If the frequency of the wave is 0.25 Hz, calculate the distance between successive crests of the wave.

  • A. A. 5.0 m
  • B. B. 40.0 m
  • C. C. 50.0 m
  • D. D. 80.0 mCorrect

Explanation

Given: speed of wave (v)=20 m/s; frequency of wave (f)=0.25Hz; wavelength=distance between successive crests. v=fλ => λ=v/f=20/0.25=80m.

Physics 2017 Objective — Question 25

The ability of a wave to spread around corners is called

  • A. A. polarisation
  • B. B. dispersion
  • C. C. diffractionCorrect
  • D. D. reflection

Explanation

The ability of a wave to spread around corners is called diffraction.

Physics 2017 Objective — Question 26

The following devices use plane mirrors in their operations, except

  • A. A. periscope
  • B. B. sextant
  • C. C. kaleidoscope
  • D. D. binocularsCorrect

Explanation

The periscope, sextant and kaleidoscope are applications of plane mirrors. Binoculars are made from lenses.

Physics 2017 Objective — Question 27

When an object is placed at the principal focus of a concave mirror, the location of the image formed is

  • A. A. between principal focus and pole
  • B. B. between principal focus and centre of curvature
  • C. C. at infinityCorrect
  • D. D. at centre of curvature

Explanation

Image of an object placed at the principal focus of a concave mirror is formed at infinity.

Physics 2017 Objective — Question 28

[Diagram: ray of light in air refracting into a denser medium] From the diagram, the correct equation for the refractive index n of the medium is

Diagram for question 28
  • A. A. n = tani
  • B. B. n = sini/sin90°Correct
  • C. C. n = sini/cos(90°-i)
  • D. D. n = sin90°C

Explanation

i=r=[law of reflection]. From the diagram, r+90°=180° (angles on a straight line); r+r2=180°-90°=90° => r2=90°-i. The refractive index of medium = sini/sinr2 = sini/sin(90°-i) = sini/cosi = tani. (Note: the official answer key states B, n=sini/sin90°.)

Physics 2017 Objective — Question 29

A ray of light travels from air to water. The refractive index of water is given by the expression

  • A. A. velocity in water/velocity in air
  • B. B. sin of angle of refraction/sine of angle of incidence
  • C. C. apparent depth/real depth
  • D. D. wavelength in air/wavelength in waterCorrect

Explanation

For a ray of light travelling from air to water, na/nw = sini/sinr = velocity in air/velocity in water = real depth/apparent depth = wavelength in air/wavelength in water.

Physics 2017 Objective — Question 30

A lens that is thinner at the middle is a A. diverging lens B. converging lens C. plano-convex D. converging meniscus

  • A. A. diverging lensCorrect
  • B. B. converging lens
  • C. C. plano-convex
  • D. D. converging meniscus

Explanation

A diverging (concave) lens is thinner at the centre than at the edges.

Physics 2017 Objective — Question 31

Which of the following electromagnetic waves has the longest wavelength?

  • A. A. Radio wavesCorrect
  • B. B. Gamma rays
  • C. C. Infrared waves
  • D. D. Ultraviolet rays

Explanation

Radio waves have the longest wavelength and lowest frequency among electromagnetic waves.

Physics 2017 Objective — Question 32

The amplitude of a sound wave determines its

  • A. A. frequency
  • B. B. quality
  • C. C. loudnessCorrect
  • D. D. pitch

Explanation

The amplitude of a sound wave determines its loudness.

Physics 2017 Objective — Question 33

As the air column of length L in an air pipe decreases, the frequency of the stationary wave emitted

  • A. A. decreases
  • B. B. increasesCorrect
  • C. C. varies as L²
  • D. D. varies as √L

Explanation

As the length of the air column, L, in an air pipe decreases, the frequency of the stationary wave emitted increases (frequency is inversely proportional to length).

Physics 2017 Objective — Question 34

A positively charged glass rod is placed near the cap of a positively charged electroscope. The divergence of the leaf is observed to

  • A. A. decrease
  • B. B. increaseCorrect
  • C. C. remain the same
  • D. D. increase and collapse immediately

Explanation

When a positively charged rod is brought near a positively charged (like-charged) electroscope, the divergence of the leaf increases due to electrostatic repulsion/induction.

Physics 2017 Objective — Question 35

Capacitors are used in the following devices, except

  • A. A. water pumping machinesCorrect
  • B. B. ceiling fans
  • C. C. electric irons
  • D. D. television sets

Explanation

Capacitors are not used in electric iron. (Note: per the source, capacitors are not used in water pumping machines nor electric irons in some contexts; the official answer given is A.)

Physics 2017 Objective — Question 36

[Diagram: circuit with 6Ω and 4Ω resistors in parallel, and a 10Ω resistor, connected to a 12V battery] Calculate the current, I.

Diagram for question 36
  • A. A. 0.60A
  • B. B. 0.97ACorrect
  • C. C. 1.03A
  • D. D. 5.00 A

Explanation

The 6Ω and 4Ω resistors are in parallel connection, so their resultant resistance is: 1/R46 = 1/6+1/4 = 0.4167, R46=2.4Ω. There is now the 10Ω resistor in series with this. Total resistance RT = (2.4+10)Ω = 12.4Ω. From V=IR: I=V/RT=12/12.4=0.97A.

Physics 2017 Objective — Question 37

[Same circuit as above] Determine the potential difference, V, across the parallel resistors.

Diagram for question 37
  • A. A. 2.0 V
  • B. B. 2.3 VCorrect
  • C. C. 3.0V
  • D. D. 9.7V

Explanation

The total potential = (Potential across the parallel conductor) + (Potential across the 10Ω resistor). Potential across the 10Ω resistor V=IR=0.97x10=9.7V. Therefore, the potential across the parallel resistors (12-9.7)V = 2.3V, or equivalently V46=IxR46=0.97x2.4=2.3V.

Physics 2017 Objective — Question 38

A galvanometer of internal resistance 50Ω and full scale deflection of 20mA is converted into a voltmeter by connecting a resistor of resistance 1950Ω in series to it. Calculate the maximum voltage that can be read by the voltmeter.

  • A. A. 20V
  • B. B. 30V
  • C. C. 38V
  • D. D. 40VCorrect

Explanation

Given: Rg=Resistance of the galvanometer=50Ω; current in circuit=20mA=0.02A; Resistance(R) of the resistor=1950Ω; voltage read by voltmeter=V=IRG+IR=I(RG+R)=(0.02x50)+(0.02x1950)=1+39=40V.

Physics 2017 Objective — Question 39

In the wiring of houses, the fuse is connected to the wire coloured

  • A. A. blue
  • B. B. brownCorrect
  • C. C. yellow
  • D. D. green

Explanation

In the wiring of houses, the fuse is connected to the live wire, which is coloured brown, and in some cases red.

Physics 2017 Objective — Question 40

Which of the following factors does not affect the electric resistance of a wire?

  • A. A. Length
  • B. B. MassCorrect
  • C. C. Temperature
  • D. D. Cross-sectional area

Explanation

The electric resistance of a wire does not depend on the mass of the wire, but it depends on (i) temperature of wire (ii) length of wire (iii) cross-sectional area of wire.

Physics 2017 Objective — Question 41

Which of the following factors will increase the sensitivity of a moving coil meter?

  • A. A. A Strong spring
  • B. B. Low number of turns
  • C. C. Small area of oil
  • D. D. Soft iron coreCorrect

Explanation

Soft iron core increases the sensitivity of a moving coil meter.

Physics 2017 Objective — Question 42

In order to prevent bar magnets from losing their strength, they are stored with keepers such that the two bars are placed with A like poles facing each other and the keepers placed at their ends. B. like poles facing each other and the keepers placed between them.

  • A. A. like poles facing each other and the keepers placed at their ends
  • B. B. like poles facing each other and the keepers placed between them
  • C. C. unlike poles facing each other and the keepers placed at their endsCorrect
  • D. D. unlike poles facing each other and the keepers placed between them

Explanation

In order to prevent bar magnets from losing their strength, they are stored in pairs with keepers such that the two bars are placed with unlike poles facing each other and the keepers placed between them.

Physics 2017 Objective — Question 43

The resonant frequency of an a.c. circuit is 1000 kHz. If each of the capacitance and inductance in the circuit is reduced by 50% and no other changes are made, the resonant frequency will become

  • A. A. 250 kHz
  • B. B. 750 kHz
  • C. C. 1000 kHz
  • D. D. 2000 kHzCorrect

Explanation

f0=1/(2π√LC). f0∝1/√LC. Given f1=1000kHz, L1=L, C1=C; L2=L/2, C2=C/2 (both reduced by 50%). 1000√(L1C1)=f2√(L2C2) => f2 = 1000√(L1C1)/√(L2C2) = 1000x√(LC)/√((L/2)(C/2)) = 1000x2=2000kHz.

Physics 2017 Objective — Question 44

The energy, E stored in an inductor of inductance L when current I passes through it is given by the equation

  • A. A. E=½LI²Correct
  • B. B. E=LI²
  • C. C. E=½LI
  • D. D. E=½L²I

Explanation

The energy stored in an inductor is given as E=½LI², where I=current and L=Inductor of an inductance.

Physics 2017 Objective — Question 45

Eddy currents can be reduced by

  • A. A. using coil of high resistance
  • B. B. winding the coil on a soft iron core
  • C. C. creating holes in the metal platesCorrect
  • D. D. using coil of low resistance

Explanation

Eddy currents can be reduced by creating holes or laminating (slots) in the metal plates.

Physics 2017 Objective — Question 46

An electron moves with a speed of 2.0x10⁶ ms⁻¹ in a straight line. Calculate the wavelength of the electron wave. [mass of an electron=9.1x10⁻³¹kg] [Planck's constant=6.6x10⁻³⁴Js]

  • A. A. 3.63x10⁻¹⁰mCorrect
  • B. B. 6.51x10⁻⁹m
  • C. C. 4.24x10⁻⁸m
  • D. D. 7.25x10⁻¹⁰m

Explanation

Using de Broglie's equation, λ=h/mv = 6.6x10⁻³⁴/(9.1x10⁻³¹x2x10⁶) = 3.63x10⁻¹⁰m.

Physics 2017 Objective — Question 47

Oxidation of the filament in a light bulb is prevented by the introduction of

  • A. A. hydrogen
  • B. B. oxygen
  • C. C. argonCorrect
  • D. D. mercury vapour

Explanation

Argon or nitrogen is used to prevent the oxidation of the filament in light bulbs.

Physics 2017 Objective — Question 48

In a cathode ray tube, the function of the X-plates is to

  • A. A. deflect the electron beam horizontallyCorrect
  • B. B. deflect the electron beam vertically
  • C. C. reflect the electron beam
  • D. D. generate sinusoidal waves

Explanation

The function of the X-plates in a cathode ray tube is to deflect the electron beam horizontally.

Physics 2017 Objective — Question 49

A nuclide represented as ⁷⁰₃₂X has a neutron-proton ratio of

  • A. A. 0.5
  • B. B. 0.8
  • C. C. 1.2Correct
  • D. D. 5

Explanation

70=[number of neutrons]+proton, and 32=no of protons. Therefore, number of neutrons=70-32=38. Ratio of neutron to proton = number of neutrons/number of protons = 38/32 = 1.2.

Physics 2017 Objective — Question 50

Neutrons are used to induce artificial radioactivity because they

  • A. A. are energetic
  • B. B. have no chargeCorrect
  • C. C. have no mass
  • D. D. are ionizing

Explanation

Neutrons are used to induce artificial radioactivity because they have no charge, so they can penetrate the nucleus without being repelled by it (unlike positively charged particles being repelled by the positive nucleus).

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