WAEC Physics 2017 Objective — Question 36

Question 36 of 50 from the West African Examinations Council (WAEC) Physics 2017 Objective paper, with the correct answer and a full explanation.

[Diagram: circuit with 6Ω and 4Ω resistors in parallel, and a 10Ω resistor, connected to a 12V battery] Calculate the current, I.

A. A. 0.60A
B. B. 0.97ACorrect
C. C. 1.03A
D. D. 5.00 A

Explanation

The 6Ω and 4Ω resistors are in parallel connection, so their resultant resistance is: 1/R46 = 1/6+1/4 = 0.4167, R46=2.4Ω. There is now the 10Ω resistor in series with this. Total resistance RT = (2.4+10)Ω = 12.4Ω. From V=IR: I=V/RT=12/12.4=0.97A.

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