Question

9(d)(i) The table below gives readings of the resistance and pressure of a platinum resistance thermometer and a gas thermometer, respectively, when immersed in the same liquid bath (ice point: resistance 5.67Ω/pressure 7.13x10^4Pa; steam point: resistance 7.75Ω/pressure 9.74x10^4Pa). Use this data to determine the temperature of the bath on the: (a) Resistance thermometer; (b) gas thermometer

Accepted Answer

On resistance thermometer (with intermediate readings R=7.43Ω): (7.75-5.67)/(7.43-5.67) = (373-273)/(R-273). 2.08/1.76 = 100/(R-273). (R-273) = (100x1.76)/2.08 = 84.62. R=84.62+273=357.62K.
On gas thermometer (with intermediate reading G=9.33x10^4Pa): (375-273)/(G-273) = (9.74x10^4-7.13x10^4)/(9.33x10^4-7.13x10^4). 100/(G-273) = (2.61x10^4)/(2.2x10^4). G-273 = (100x2.2)/2.61 = 84.29. G=84.29+273=357.29K.

WAEC Physics 2017 Theory — Question 17

Sign up free to unlock