WAEC Physics 2020 Objective — Question 24

Question 24 of 50 from the West African Examinations Council (WAEC) Physics 2020 Objective paper, with the correct answer and a full explanation.

A 500 N box rests on a horizontal floor. A constant horizontal force is exerted on the box so that it moves through 8 m. If the coefficient of kinetic friction between the floor and the box is 0.22, calculate the work done on the box.

A. 880 JCorrect
B. 440 J
C. 400 J
D. 110 J

Explanation

Given W=500N (50kg), distance d=8m, coefficient of kinetic friction (uk)=0.22. Work done = force x distance, where force = friction force = uk x mg = 0.22 x 500 x 8 = 880 J.

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