WAEC Physics 2020 Objective — Question 37
Question 37 of 50 from the West African Examinations Council (WAEC) Physics 2020 Objective paper, with the correct answer and a full explanation.
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In an electric circuit, an inductor of inductance 0.5 H and resistance 50 ohm is connected to an alternating current source of frequency 60 Hz. Calculate the impedance of the circuit.
- A. 50.0 ohm
- B. 150.5 ohm
- C. 195.0 ohmCorrect
- D. 1950.1 ohm
Explanation
Given L=0.5H, R=50 ohm, f=60Hz, required Z=? Z=sqrt(R^2+XL^2), where XL=2(pi)fL=2(pi)x60x0.5=188.52 ohm. Z=sqrt(50^2+188.52^2)=sqrt(2500+35,539.6)=sqrt(38039.79)=195.04 ohm.
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