WAEC Physics 2020 Objective — Question 50

Question 50 of 50 from the West African Examinations Council (WAEC) Physics 2020 Objective paper, with the correct answer and a full explanation.

When two cells of negligible internal resistances and equal e.m.f. denoted by E1 and E2 are connected in parallel, the combined e.m.f. E is given by

A. E = E1 + E2
B. 1/E = 1/E1 + 1/E2
C. E = E1 = E2Correct
D. E = E1/E2

Explanation

When two cells of negligible internal resistance and equal e.m.f. are connected in parallel, the combined e.m.f. E remains equal to the e.m.f. of each individual cell, i.e. E = E1 = E2.

Sign up free to unlock

Score tracking
Practice history
Saved questions
Progress dashboard
Personalized sessions
Weak-topic breakdown

…and/or go further with premium services and No Ads.

Create free account

More questions from Physics 2020 Objective More Physics past papers