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WAEC Physics 2020 Theory Past Questions

All 12 questions from the West African Examinations Council (WAEC) Physics 2020 Theory paper, with the correct answer and a full explanation for each. Free, no signup needed.

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Physics 2020 Theory — Question 1

1. An elastic material of length 3 m is to be stretched to an extension three times its original length. Calculate the force required to produce the extension if the force constant of material is 982.3 Nm^-1.

Model answer

Given: Original length l0=3m, extension e=3l0=3x3=9m. Force constant k=982.3 Nm^-1. Correlating equation: F=ke. F=982.3x9=8840.7 N.

Physics 2020 Theory — Question 2

2. In a solar panel for heat supply, state the function of each of the following parts: (a) Metal plate; (b) Thermal insulator; (c) Tubes.

Model answer

(a) Function of metal plate of solar panel: Receives and absorbs solar radiation to produce heat. (b) Thermal insulator: Minimizes heat loss to the environment. (c) Tubes of solar panel: Helps in circulating the heat.

Physics 2020 Theory — Question 3

3(a) In the design an optical fibre, what type of material is most suitable for the design of the core? (b) State one condition necessary to confine signals to the core of an optical fibre.

Model answer

(a) The material most suitable for the design of the core is pure glass (SiO2), plastic, or both. (b) To confine signal to the core of an optical fibre, the refractive index of the core must be greater than that of the cladding.

Physics 2020 Theory — Question 4

4. The velocity v of a wave in a stretched string depends on the tension T in the spring and the mass per unit length mu of the string. Obtain an expression for v in terms of T and mu, using the method of dimensions.

Model answer

Given: v is proportional to T^x mu^y, where T=Tension in the spring, mu=mass per unit length, v=velocity of a wave. Thus v=kT^x mu^y, where k is a dimensionless constant. Dimensionally: T(N)=kgm/s^2, T(N)=MLT^-2; mu=kgm^-1, mu=ML^-1. Thus, LT^-1=k[MLT^-2]^x[ML^-1]^y. LT^-1=k[m^x L^x T^-2x][M^y L^-y]. LT^-1=kM^(x+y)L^(x-y)T^-2x. Comparing the L.H.S and R.H.S terms: For M: x+y=0 (1). For L: x-y=1 (2). And for T: -1=-2x, x=1/2, and from (1): x+y=0, y=-1/2. Thus, v=kT^(1/2)mu^(-1/2), or v=k*sqrt(T/mu).

Physics 2020 Theory — Question 5

5. A satellite launched with velocity VE just escapes the earth's gravitational attraction. Given that the radius of the earth is R, show that VE = sqrt(2gR). [g=10 ms^-2]

Model answer

Given: Escape velocity VE, radius of the earth=R. To show that VE=sqrt(2gR). Analysis: When the satellite just escapes the earth's gravitational attraction, the Gravitational potential energy equals the kinetic energy of the satellite, i.e. P.E.=K.E. GmM/R = (1/2)mVE^2. GM/R = (1/2)VE^2. VE^2=2GM/R. But GM=gR^2 (from g=GM/R^2). VE^2=2gR^2/R=2gR. Therefore, VE=sqrt(2gR).

Physics 2020 Theory — Question 6

6. A bullet is fired from a gun at 30 deg. The bullet remains in flight for 25 s before touching the ground. Calculate the velocity of projection. (g=10 ms^-2)

Model answer

Given: theta=30 deg, T=25s, g=10m/s^2, required v=? Recall that Time of flight T=2usin(theta)/g. 25=2usin30/10. 250=2u(1/2). 250=u. Therefore, u=250 ms^-1.

Physics 2020 Theory — Question 7

7. State three properties of lasers that make them preferable to ordinary light beam.

Model answer

Properties of laser beams that make them preferable to ordinary light beams (any three): i. It is monochromatic i.e. having only one colour. ii. It gives more intense light/power. iii. It has a very narrow optical bandwidth. iv. It can be emitted continuously. v. It travels a very long distance without losing its intensity.

Physics 2020 Theory — Question 8

8(a)(i) Define a torque. (ii) State three factors that determine a torque. (b)(i) Define free fall. (ii) A body is thrown vertically upward from the top of a tower 40.0 m high with a velocity of 10.0 ms^-1. Calculate the time taken for the body to reach the ground. (g=10 ms^-2) (c) A cube of wood of side 8.0 cm, floats at the interface between oil and water with 2.0 cm of its lower surface below the interface as shown in the diagram below. Given that the relative densities of oil and water are 0.72 and 1.00 respectively. Calculate the mass of the wood.

Model answer

(a)(i) A torque is defined as the turning effect of force about a pivot or an axis. (ii) Factors that determine a torque: Perpendicular distance of the force from its line of action to the pivot; Direction of the force; Magnitude of the force. (b)(i) A free fall is defined as the vertical motion of a body under the influence of acceleration due to gravity, or its own weight. (ii) Given u=10m/s, height of tower=40m. Using H=ut+(1/2)gt^2, taking downward as positive from the top of the tower and the body thrown upward first: -40=10t-(1/2)(10)t^2. -40=10t-5t^2. 5t^2-10t-40=0. Divide through by 5: t^2-2t-8=0. t^2-4t+2t-8=0. t(t-4)+2(t-4)=0. (t+2)(t-4)=0. t=-2 or t=4. Since time cannot be negative, t=4 s. (c) Given: Mass of wood = mass of water displaced + mass of oil displaced. Mass of wood = (rho.V)oil + (rho.V)water, where rho_oil = density of oil = 0.72x1000=720 gcm^-3(kg/m3 equivalent), rho_water = density of water = 1x1000=1000 gcm^-3. With V_oil = volume of oil displaced = volume of portion of wood in oil = lbh = 8x8x6cm^3=384cm^3=384x10^-6 m^3. Similarly, V_water = volume of water displaced = volume of portion of wood inside water = lbh(l=b=8cm, h=2cm)=128cm^3=128x10^-6 m^3. Thus, mass of wood = [720x384+1000x128]x10^-6 = [276,480+128,000]x10^-6 = [404,480]x10^-6 = 0.404 kg.

Physics 2020 Theory — Question 9

9(a)(i) Explain resonance frequency as applied to RLC series circuit. (ii) Sketch a diagram to illustrate the variation of frequency f, with resistance R, capacitive reactance Xc and the inductive reactance XL in RLC circuit. (iii) Using the diagram drawn in 9(a)(ii), state whether the current leads, lags or is in phase with the supply voltage when (alpha) f=fo, (beta) f less than fo, (gamma) f greater than fo. (b)(i) Define Mutual inductance. (ii) The coil of an electric generator has 500 turns and 8.0 cm diameter. If it rotates in a magnetic field of density 0.25T, calculate the angular speed when its peak value is 480 V. (pi=3.142) (c)(i) Explain Eddy currents. (ii) State two practical uses of eddy currents.

Model answer

(a)(i) Resonance frequency as applied to RLC series circuit: It is the frequency of oscillation of an RLC series circuit when the capacitive reactance Xc is equal to the inductive reactance XL and the impedance Z is equal to the resistance with the current maximum and the impedance minimum. (ii) [Sketch: graph of reactance (y-axis) against frequency (x-axis), showing XL as an increasing line and Xc as a decreasing curve, intersecting at the resonance frequency fo.] (iii) Relationship between current and voltage: (alpha) When f=fo, current is in phase with the supply voltage. (beta) When f less than fo, current leads the supply voltage. (gamma) When f greater than fo, current lags the supply voltage. (b)(i) Mutual inductance is defined as the ratio of the induced e.m.f. in one coil or circuit to the time rate of change of current in the other coil. It is also defined as the production of e.m.f. in a circuit as a result of the change in the magnetic flux in an adjacent circuit linked to it. (ii) Given: Number of turns N=500 turns, diameter d=8.0cm=8x10^-2m, B=0.25T, V=480V, pi=3.142. Correlating equation: Rotational induced e.m.f of an electric generator, E.m.f.=(omega)BAN. 480=omega x 0.25 x (pi d^2/4) x 500. 480=omega x 0.25 x [(8x10^-2)^2 x pi/4] x 500. 480=6284x10^-4 (omega). omega=480/0.6284=763.84 rad/s. (c)(i) Eddy current: These are currents induced and flows within a metal block when there is a change in magnetic flux linking the block. OR They are loops of electrical current induced within conductors by changing magnetic field in the conductor. Eddy currents flow in closed loops within conductors, in planes perpendicular to the magnetic field. (ii) Practical uses of Eddy currents: Induction heating furnaces to heat objects; Automobile speedometers; Induction alternating current (AC) motors; Induction coils.

Physics 2020 Theory — Question 10

10(a)(i) Define critical angle as used in optics. (ii) State two conditions necessary for total internal reflection to occur. (iii) List three practical applications of total internal reflection. (b) State two effects of refraction. (c)(i) Define progressive waves. (ii) A plane progressive wave is represented by the equation y=0.5sin(1000(pi)t - 100(pi)x/17), where y is in millimeters, t in seconds, and x in meters. Calculate the: (alpha) frequency of the wave; (beta) wavelength of the wave; (gamma) speed of the wave.

Model answer

(a)(i) Critical angle is defined as the angle of incidence in the optically denser medium for which the angle of refraction in the less dense medium is 90 deg. i=c=critical angle when r=refracted angle=90 deg. (ii) Conditions necessary for total internal reflection to occur: light rays must travel from a denser medium to a less dense medium e.g. glass to air or glass to water or water to air; the angle of incidence in the denser medium must be greater than the critical angle (i>c). (iii) Practical applications of total internal reflection (TIR): Optical fibres used in the telecommunication field; Prism periscopes for viewing overhead objects; Prism Binoculars for viewing distance objects; Fish eye view; Transmission of radio signals. (b) Effects of refraction: Change in the direction of a wave; Change in the speed of a wave; Object appears raised when viewed above the water. (c)(i) A progressive wave is defined as a disturbance which travels through a medium that enables energy to be transferred from its source to another (without the particles of the medium being transferred). (ii) Given the wave equation y=0.5sin(1000(pi)t-100(pi)x/17): (alpha) To find the frequency of the wave, we recall the general equation of a progressive wave along the positive x-axis, i.e. y=Asin(omega*t - 2(pi)x/lambda) = Asin(2(pi)ft - 2(pi)x/lambda). Comparing this with the given equation, we have 2(pi)f=1000(pi), so f=1000(pi)/2(pi)=500 Hz. (beta) To find the wavelength of the wave, again we compare the two wave equations, i.e. 2(pi)x/lambda = 100(pi)x/17. So 2/lambda=100/17. lambda x 100 = 17x2. lambda=34/100=0.34 m. (gamma) To calculate the speed of the wave, using v=f*lambda: v=500x0.34, v is approximately 170 m/s.

Physics 2020 Theory — Question 11

11(a) In an experiment to measure the specific latent heat of vapourization of water, a student places a heater in a beaker containing water. The beaker stands on an electronic balance so that the mass of the beaker and water could be measured. The heater is switched on and readings taken every 100 s when the water starts boiling. The table below shows the reading (Time(s): 0,100,200,300,400 | Reading on balance(g): 203.22, 201.62, 199.79, 198.25, 196.50). (i) Fill in the mass of water evaporated. (ii) Given that the heater supplies energy at the rate of 38 J/s, fill in the values of the energy supplied by the heater in 100 s, 200 s, 300 s and 400 s. (iii) Plot a graph of energy supplied on the vertical axis and mass of water evaporated on the horizontal axis, starting both axes from the origin (0,0). I. Determine the slope of the graph. II. What does the value of the slope mean? (b)(i) Explain what is meant by saturated vapour pressure. (ii) State the factor that affects saturated vapour pressure.

Model answer

(a)(i) Mass of water evaporated = (New mass) - (Initial mass), calculated at each time interval from the balance readings: at 100s, mass evaporated=203.22-201.62=1.60g; at 200s, =203.22-199.79=3.43g; at 300s,=203.22-198.25=4.96g; at 400s,=203.22-196.50=6.72g. (ii) Energy supplied by heater = rate of energy supply x time = (38 J/s) x time. At 100s: 3800J; at 200s: 7600J; at 300s: 11,400J; at 400s: 15,200J (values filled based on the given rate of 38 J/s, consistent with the table's progression pattern of 0, 38.00, 76.00, 114.00, 152.00 in the units indicated in the table, i.e. in units of 10^2 J). (iii) I. Slope of the graph = (Delta Q)/(Delta m) = (Q2-Q1)/(m2-m1) = (11.2-2.0)x10^3 / (5.0-0.9) = 9.2x10^3/4.1 = 2.24x10^3 J/g. II. Meaning of the value of the slope of a graph: The slope = 2.24x10^3 J of heat is needed to evaporate 1 g of water at constant temperature; this represents the specific latent heat of vaporization of water. (b)(i) Saturated vapour pressure: The process of evaporation in a closed container will proceed until there are as many molecules returning to liquid as there are escaping. At this point, the vapour is said to be saturated. This is called the saturated vapour pressure of the liquid at that temperature. (ii) Factor affecting saturated vapour pressure: Temperature. Vapour pressure increases as the temperature increases and vice-versa.

Physics 2020 Theory — Question 12

12(a)(i) Define isotopes. (ii) Mention two uses of radioactive tracers in each of the following areas: (alpha) Medicine; (beta) Industry; (gamma) Agriculture. (b) When light of frequency 5.4x10^14 Hz is incident on a metal surface, the maximum energy of the emitted electron is 1.2x10^-19 J. Calculate the minimum frequency of radiator for which electrons can be emitted. (h=6.6x10^-34 Js) (c) State three features common to electromagnetic waves. (d)(i) Mention four components of the nuclear reactor. (ii) State the function of each of the components stated in 12(d)(i).

Model answer

(a)(i) Isotopes are atoms of the same element with the same number of protons (atomic number) but different number of neutrons (mass number). (ii) Uses of radioactive tracers in medicine: Monitoring the function of the thyroid gland and other organs; Detection of blood clots in the brain; Diagnosis and treatment of disease; Sterilization of medical equipment. Uses of tracers in industry: Leakages in underground pipes; Wear and tear of machinery; Environmental pollution. Uses of tracers in agriculture: Determination of plants absorption of mineral elements; Study of the mechanism of photosynthesis; Seed preservation; Sterilization of insects; Food preservation. (b) Given: f=5.4x10^14 Hz, Emax=1.2x10^-19 J, required fo=? Using Emax=hf-Wo, E=hf-hfo=h(f-fo), so fo=f-(1.2x10^-19)/(6.6x10^-34)=5.4x10^14-0.1818x10^15=5.4x10^14-1.188x10^14=3.6x10^14 Hz. (c) Features common to electromagnetic waves: They are transverse waves; travel with the speed of light in vacuum; undergo refraction, reflection, diffraction, polarization and interference; travel through vacuum. (d)(i) Components of the nucleus reaction/nuclear reactor: Uranium fuel; Graphite moderator; Boron/Control rod; Coolant; Heat exchanger; Shield. (ii) Functions of the components of the nuclear reactor: Uranium rods - serves as fuel for the nuclear reaction; Graphite moderator - controls neutron population; Coolant - reduces the excessive heat produced in the nuclear reactor; Heat exchanger - converts the heat energy produced to other forms; Shield - to protect the operator and surrounding against extraneous radiations.

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