WAEC Physics 2025 Objective — Question 13
Question 13 of 51 from the West African Examinations Council (WAEC) Physics 2025 Objective paper, with the correct answer and a full explanation.
Advertisement
A constant voltage source in the circuit below supplies a sinusoidal alternating e.m.f. The voltages marked against the components are the peak values. Determine the peak value of the applied e.m.f.
- A. 11.0V
- B. 9.0V
- C. 8.0V
- D. 7.1VCorrect
Explanation
V = √(VR²+(VL-VC)²) = √(3²+(6-2)²) = √(9+16) = √25 = 5V (rms). Peak value V₀ = Vrms×√2 = 5×√2 = 7.1V.
Advertisement
Sign up free to unlock
- Score tracking
- Practice history
- Saved questions
- Progress dashboard
- Personalized sessions
- Weak-topic breakdown
…and/or go further with premium services and No Ads.