WAEC Physics 2025 Objective — Question 44
Question 44 of 51 from the West African Examinations Council (WAEC) Physics 2025 Objective paper, with the correct answer and a full explanation.
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A radium nuclide decays by emitting alpha particles as shown below: ²²⁶₈₈Ra → X + ⁴₂He. Determine the daughter nuclide.
- A. ²²²₈₆XCorrect
- B. ²²²₈₈X
- C. ²³⁰₈₆X
- D. ²³⁰₈₈X
Explanation
By conservation of mass number: 226 = a+4 → a = 222. By conservation of atomic number: 88 = b+2 → b = 86. Daughter nuclide is ²²²₈₆X.
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