JAMB Chemistry 2012 Objective — Question 23

Question 23 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2012 Objective paper, with the correct answer and a full explanation.

The oxidation number of boron in NaBH4 is

A. -3
B. -1
C. +1
D. +3Correct

Explanation

NaBH4 is sodium tetrahydridoborate (III). Na=+1, H=−1 (each of 4 hydrogens). +1+B+(−1×4)=0 ⇒ 1+B−4=0 ⇒ B=+3.

Sign up free to unlock

Score tracking
Practice history
Saved questions
Progress dashboard
Personalized sessions
Weak-topic breakdown

…and/or go further with premium services and No Ads.

Create free account

More questions from Chemistry 2012 Objective More Chemistry past papers