JAMB Chemistry 2012 Objective — Question 24

Question 24 of 50 from the Joint Admissions and Matriculation Board (JAMB) Chemistry 2012 Objective paper, with the correct answer and a full explanation.

2Na2O2(s) + 2H2O(l) →4NaOH(s) + O2(g). The substance that is oxidized in the reaction above is

A. 2Na2O2(s)Correct
B. NaOH(aq)
C. H2O(l)
D. O2(g)

Explanation

In this reaction, the oxidation number of oxygen in Na2O2 (peroxide, −1) increases to 0 in O2, meaning Na2O2 is oxidized.

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