Free account: track your progress — Sign up free

WAEC Chemistry 2023 Objective Past Questions

All 50 questions from the West African Examinations Council (WAEC) Chemistry 2023 Objective paper, with the correct answer and a full explanation for each. Free, no signup needed.

Advertisement

Chemistry 2023 Objective — Question 1

Which of the following laws or theory cannot be explained by the application of the kinetic theory of gases?

  • A. Dalton's atomic theoryCorrect
  • B. Charles' law
  • C. Gay-Lussac's law
  • D. Boyle's law

Explanation

As they are gas laws, Charles' law, Gay-Lussac's law and Boyle's law can be explained by the kinetic theory of gases. Dalton's atomic theory is not a gas law.

Chemistry 2023 Objective — Question 2

The primary component of natural gas is

  • A. butane
  • B. ethane
  • C. methaneCorrect
  • D. propane

Explanation

Methane is the main component of natural gas. It makes up 70–90% of natural gas. The other significant components are ethane, propane and butane; nitrogen, carbon dioxide, helium and trace amounts of hydrogen sulphide and odorants can also be present.

Chemistry 2023 Objective — Question 3

Thermal cracking of alkanes usually

  • A. involves decompositionCorrect
  • B. is an exothermic process
  • C. produces only small alkanes
  • D. requires hydrogen

Explanation

In thermal cracking, high temperatures (usually 450–750°C) and pressures (up to about 70 atmospheres) are used to break large hydrocarbons into smaller ones — this is a decomposition process.

Chemistry 2023 Objective — Question 4

Carbon is deposited in the exhaust pipes of vehicles because of

  • A. contamination of petrol with diesel
  • B. presence of carbon in petrol
  • C. presence of additives in petrol
  • D. incomplete combustion of petrolCorrect

Explanation

The presence of carbon deposits in the exhaust pipes of cars is a result of incomplete combustion of the fuel.

Chemistry 2023 Objective — Question 5

How many moles of copper would be deposited by passing 1 Faraday of electricity through a CuCl2 solution?

  • A. 2
  • B. 1
  • C. 0.5Correct
  • D. 0.25

Explanation

Cu2+ + 2e− → Cu. Since 2 moles of electrons (2F) are required to deposit 1 mole of copper, the amount deposited using 1F = (1 mol/2F) × 1F = 0.5 mol.

Chemistry 2023 Objective — Question 6

Alkenes can be manufactured by

  • A. addition of hydrogen to unsaturated vegetable oils
  • B. the cracking of hydrocarbonsCorrect
  • C. polymerization reactions
  • D. the combustion of alkanes

Explanation

Alkenes can be obtained from the cracking of hydrocarbons. (Combustion of alkanes produces CO2 and H2O; addition of hydrogen to vegetable oils produces margarine, using a nickel catalyst at about 200°C.)

Chemistry 2023 Objective — Question 7

Petrochemistry is an example of

  • A. pure chemistry
  • B. applied chemistryCorrect
  • C. biochemistry
  • D. environmental chemistry

Explanation

Petrochemistry is a branch of applied chemistry that focuses on how crude oil and natural gas are transformed into raw materials and other useful products.

Chemistry 2023 Objective — Question 8

Species that occur in a reaction pathway but not in the overall reaction are known as

  • A. products
  • B. inhibitors
  • C. reactants
  • D. intermediatesCorrect

Explanation

Species that occur in a reaction pathway but not in the overall (net) reaction equation are known as intermediates.

Chemistry 2023 Objective — Question 9

Which of the following statements is correct?

  • A. An alkane with 49 carbon atoms contains 100 hydrogen atomsCorrect
  • B. Addition reactions occur between alkanes and chlorine
  • C. Butane has a lower boiling point than pentane
  • D. Pentane has five isomers

Explanation

Since the general formula of alkanes is CnH2n+2, an alkane with 49 carbon atoms will contain (2×49)+2 = 100 hydrogen atoms. The reaction between alkanes and chlorine is a substitution reaction, not addition. Butane is heavier than propane so has a higher boiling point than propane (not relevant to this comparison — butane's boiling point is in fact higher than propane's, and lower than pentane's, so option C is false). Pentane has three isomers, not five.

Chemistry 2023 Objective — Question 10

The best indicator to use for the titration of ethanoic acid with sodium hydroxide is

  • A. methyl red
  • B. methyl orange
  • C. phenolphthaleinCorrect
  • D. screened methyl orange

Explanation

A titration involving a weak acid (such as ethanoic acid) and a strong base (such as sodium hydroxide) requires phenolphthalein as the indicator.

Chemistry 2023 Objective — Question 11

The reduction half equation of the following reaction is: Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s)

  • A. CuSO4(s) + H2O(l) → Cu2+(aq) + SO4²⁻(aq)
  • B. Cu2+(aq) + 2e⁻ → Cu(s)Correct
  • C. Cu2+(aq) + e⁻ → Cu(s)
  • D. Zn(s) → Zn2+(aq) + 2e⁻

Explanation

Zn + CuSO4 → ZnSO4 + Cu. Ionically: Zn + Cu2+ → Zn2+ + Cu. Reduction half equation: Cu2+ + 2e⁻ → Cu. (Oxidation half equation: Zn → Zn2+ + 2e⁻.)

Chemistry 2023 Objective — Question 12

If 100 cm3 of a saturated solution of sodium tetraoxosulphate (VI) at 30°C contains 10.5 g of the salt, what would be its solubility at this temperature? [Na2SO4 = 142]

  • A. 0.57 mol dm⁻³
  • B. 0.60 mol dm⁻³
  • C. 0.74 mol dm⁻³Correct
  • D. 2.15 mol dm⁻³

Explanation

Mole = 10.5 g ÷ 142 g/mol = 0.0739 mol. Since 0.0739 mol saturates 100 cm3 at 30°C, 1000 cm3 (1 dm3) at the same temperature contains (0.0739/100)×1000 = 0.739 mol. Solubility ≈ 0.74 mol dm⁻³.

Chemistry 2023 Objective — Question 13

An example of a crystalline substance that does not possess water of crystallization is

  • A. potassium trioxonitrate (V)Correct
  • B. sodium trioxocarbonate (IV)
  • C. iron (II) tetraoxosulphate (VI)
  • D. sodium tetraoxosulphate (VI)

Explanation

Examples of salts without water of crystallization include potassium nitrate, barium sulphate and sodium nitrate.

Chemistry 2023 Objective — Question 14

The salt solution formed from a reaction between ethanoic acid and sodium hydroxide solution would be

  • A. acidic
  • B. basicCorrect
  • C. neutral
  • D. amphoteric

Explanation

A salt solution formed from a reaction between a weak acid (such as ethanoic acid) and a strong base (such as sodium hydroxide) will be alkaline/basic. (If the reaction were between a strong acid and a weak base, the resulting salt solution would be acidic.)

Chemistry 2023 Objective — Question 15

Which of the following reactions represents the hydrolysis of an alkanoate?

  • A. CH3COOH + C2H5OH ⇌ CH3COOC2H5 + H2O
  • B. CH3COOC2H5 + H2O ⇌ CH3COO⁻ + C2H5OH
  • C. CH3COOCH2CH3 + H2O ⇌ CH3COOH + CH3CH2OHCorrect
  • D. CH3COOH + OH⁻ ⇌ CH3COO⁻ + H2O

Explanation

The hydrolysis of an alkanoate (ester) yields the constituent alkanoic acid and alkanol: RCOOR' + H2O ⇌ RCOOH + R'OH. For example, hydrolysis of ethyl ethanoate: CH3COOCH2CH3 + H2O ⇌ CH3COOH + CH3CH2OH.

Chemistry 2023 Objective — Question 16

Which of the following statements about the collision theory is correct?

  • A. All collisions bring about reactions
  • B. Rate of reaction is proportional to the number of effective collisionsCorrect
  • C. Collision of molecules will split the molecules to react
  • D. Ineffective collision brings about chemical reaction

Explanation

Only effective collisions bring about reactions. The higher the number of such collisions, the higher the reaction rate.

Chemistry 2023 Objective — Question 17

Why are H2SO4 and CaCl2 not suitable for drying ammonia gas? They

  • A. are poisonous
  • B. are corrosive
  • C. react with the gasCorrect
  • D. pollute the gas

Explanation

H2SO4 and CaCl2 are not suitable for drying ammonia because they react with the gas. As a rule, an alkaline gas should not be dried with an acidic substance, and an acidic gas should not be dried with an alkaline substance.

Chemistry 2023 Objective — Question 18

Which of the following equations does not illustrate correctly one of the reactions of chlorine?

  • A. H2S + Cl2 → 2HCl + S
  • B. Cl2 + 2NaOH → NaCl + NaClO + H2O
  • C. Cl2 + 2NaF → 2NaCl + F2Correct
  • D. Ca(OH)2 + Cl2 → CaOCl2 + H2O

Explanation

Fluorine is more reactive than chlorine, so chlorine cannot displace fluorine from sodium fluoride, as portrayed in option C.

Chemistry 2023 Objective — Question 19

How many unpaired electrons are present in ₂₆Fe³⁺?

  • A. 2
  • B. 3
  • C. 4
  • D. 5Correct

Explanation

₂₆Fe = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶. The two 4s electrons and one 3d electron are removed to form Fe³⁺: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵. The five 3d electrons are all unpaired, so Fe³⁺ has five unpaired electrons.

Chemistry 2023 Objective — Question 20

Going down group II in the periodic table normally

  • A. shielding effect increasesCorrect
  • B. melting point increases
  • C. ionization energy increases
  • D. electronegativity increases

Explanation

Going down group II: shielding effect increases; melting point decreases; ionization energy decreases; electronegativity decreases. Only 'shielding effect increases' (option A) is a correct trend among those listed — the other three options describe the opposite of the actual trend.

Chemistry 2023 Objective — Question 21

Which of the following elements has its valence electrons in the s-orbital?

  • A. SodiumCorrect
  • B. Carbon
  • C. Phosphorus
  • D. Aluminium

Explanation

₁₁Na = 1s² 2s² 2p⁶ 3s¹; ₆C = 1s² 2s² 2p²; ₁₅P = 1s² 2s² 2p⁶ 3s² 3p³; ₁₃Al = 1s² 2s² 2p⁶ 3s² 3p¹. Sodium has its valence electron in the s-orbital, while the others have valence electrons in both s and p orbitals.

Chemistry 2023 Objective — Question 22

The periodic property that is used to determine whether a covalent molecule is polar or not is

  • A. atomic radius
  • B. electron affinity
  • C. electronegativityCorrect
  • D. ionization energy

Explanation

Electronegativity is used to investigate the nature of a bond: if the difference between the electronegativities of the bonded atoms is less than 0.5, the bond is non-polar covalent; from 0.5 to 1.7, it is polar covalent; greater than 1.7, it is ionic.

Chemistry 2023 Objective — Question 23

The following steps are scientific methods except

  • A. analysis
  • B. open-mindednessCorrect
  • C. experimentation
  • D. problem identification

Explanation

Open-mindedness is a scientific attribute, not a scientific method in itself.

Chemistry 2023 Objective — Question 24

Isoelectronic species have the same number of

  • A. electronsCorrect
  • B. neutrons
  • C. protons
  • D. ions

Explanation

Isoelectronic species have the same number of electrons. For example, Ne, Na⁺, Mg²⁺, Al³⁺, F⁻, O²⁻ and N³⁻ each contain 10 electrons and are therefore isoelectronic.

Chemistry 2023 Objective — Question 25

An element X has two isotopes, ⁶⁵₃₀X and ⁶⁶₃₀X with relative abundance of 60% and 40% respectively. The relative atomic mass of X is

  • A. 65.00
  • B. 65.40Correct
  • C. 65.50
  • D. 66.00

Explanation

R.A.M. = (mass₁×%₁ + mass₂×%₂)/100 = (65×60 + 66×40)/100 = (3900+2640)/100 = 6540/100 = 65.4

Chemistry 2023 Objective — Question 26

The pair of compounds that belongs to the same homologous series is

  • A. C3H8 and C3H6
  • B. C4H10 and C5H10
  • C. C2H4 and C4H10
  • D. C2H6 and C4H10Correct

Explanation

C3H8 (propane, an alkane) and C3H6 (propene, an alkene) do not belong to the same series; same for C4H10 (butane, alkane) and C5H10 (pentene, alkene); and for C2H4 (ethene, alkene) and C4H10 (butane, alkane). C2H6 (ethane) and C4H10 (butane) both belong to the alkane family, so they are in the same homologous series.

Chemistry 2023 Objective — Question 27

A consequence of global warming is

  • A. floodingCorrect
  • B. water pollution
  • C. air pollution
  • D. high humidity

Explanation

Flooding is a major consequence of global warming.

Chemistry 2023 Objective — Question 28

Which of the following gases has the lowest rate of diffusion? [H=1.0, C=12.0, N=14.0, O=16.0]

  • A. Nitrogen
  • B. Ammonia
  • C. OxygenCorrect
  • D. Methane

Explanation

N2 = 14×2 = 28; NH3 = 14+(1×3) = 17; O2 = 16×2 = 32; CH4 = 12+(1×4) = 16. The heavier a gas, the lower its rate of diffusion. Oxygen is the heaviest here, so it has the lowest diffusion rate.

Chemistry 2023 Objective — Question 29

The gas that is less dense than air is

  • A. carbon (IV) oxide
  • B. nitrogenCorrect
  • C. chlorine
  • D. oxygen

Explanation

For a gas to be less dense than air, its RMM should be less than 28.8 (approx. average molar mass of air). CO2 = 44, N2 = 28, Cl2 = 71, O2 = 32. Only nitrogen is less dense than air here.

Chemistry 2023 Objective — Question 30

Which of the following equimolar solutions has the highest conductivity?

  • A. H2CO3(aq)
  • B. H2SO4(aq)Correct
  • C. NaOH(aq)
  • D. CH3COONa(aq)

Explanation

H2SO4 is a strong acid that fully dissociates, giving it the highest conductivity. H2CO3 has the lowest conductivity since it is a weak acid that only dissociates slightly.

Chemistry 2023 Objective — Question 31

What takes place at the cathode during electrolysis?

  • A. Anions lose electrons
  • B. Anions are oxidized
  • C. Cations are dischargedCorrect
  • D. Cations lose electrons

Explanation

At the cathode, reduction occurs — cations gain electron(s) and are discharged. (At the anode, oxidation occurs — anions lose electron(s) and are discharged.)

Chemistry 2023 Objective — Question 32

How many grammes of NaOH(s) would be needed to produce 100.0 cm3 of a 0.20 mol dm⁻³ NaOH(aq)? [NaOH=40.0]

  • A. 0.02 g
  • B. 0.80 gCorrect
  • C. 20.0 g
  • D. 800.0 g

Explanation

Volume = 100 cm3 = 0.1 dm3. Mole of NaOH = 0.20 mol dm⁻³ × 0.1 dm3 = 0.02 mol. Mass = 0.02 mol × 40 g/mol = 0.80 g.

Chemistry 2023 Objective — Question 33

The formation of a bond between hydrogen and a highly electronegative atom results in

  • A. polarityCorrect
  • B. dipole
  • C. metallic bond
  • D. electrovalent bond

Explanation

Between hydrogen and a very small, highly electronegative atom (nitrogen, oxygen or fluorine), a hydrogen bond is formed — hydrogen bonding results from bond polarity.

Chemistry 2023 Objective — Question 34

The molecule that has a non-polar covalent bond is

Diagram for question 34
  • A. H2O
  • B. HCl
  • C. NH3
  • D. Cl2Correct

Explanation

Since the electronegativity difference between the two identical chlorine atoms in Cl2 is zero, the bond is non-polar. The same applies to F2, Br2, I2, N2, O2 and H2.

Chemistry 2023 Objective — Question 35

Use the following information to answer this question. Which of the elements in the table below would react more readily with chlorine?

  • A. W and X onlyCorrect
  • B. W and Z only
  • C. X and Z only
  • D. Y and Z only

Explanation

Chlorine (being electronegative) reacts readily with elements that lose electrons easily. A higher ionization energy means it is harder to lose an electron. Since W and X have the lowest ionization energies in the table, they lose electrons most easily and so react most readily with chlorine.

Chemistry 2023 Objective — Question 36

The relative molar mass of a gaseous hydrocarbon is 30. Determine its vapour density.

  • A. 15Correct
  • B. 30
  • C. 60
  • D. 45

Explanation

Vapour density = ½ × Relative molecular mass = ½ × 30 = 15.

Chemistry 2023 Objective — Question 37

Consider the following reaction equation: 2SO3(g) → 2SO2(g) + O2(g); ΔH = +198 kJ mol⁻¹. Which of the following statements about the reaction is correct?

  • A. The reaction is exothermic
  • B. The reaction container would feel warm
  • C. 198 kJ of energy is given off
  • D. 198 kJ of energy is absorbedCorrect

Explanation

Since ΔH is positive, the reaction is endothermic, not exothermic — heat is absorbed, not released. An endothermic reaction container would feel colder, not warmer.

Chemistry 2023 Objective — Question 38

Which of the following properties does not give evidence of the kinetic theory of matter?

  • A. Evaporation
  • B. Diffusion
  • C. PolymerizationCorrect
  • D. Melting

Explanation

Evaporation, diffusion and melting give evidence of the kinetic theory of matter (particles in constant motion); polymerization does not.

Chemistry 2023 Objective — Question 39

A compound that could be dried by using conc. tetraoxosulphate (VI) acid and not by calcium oxide is likely to be

  • A. a salt
  • B. a base
  • C. an alkane
  • D. an acid anhydrideCorrect

Explanation

It is likely to be an acid anhydride (an acidic gas). An acidic gas should not be dried with an alkaline/basic drying agent (like calcium oxide) since they would react — but it can be dried with an acidic drying agent such as concentrated H2SO4. (See the reasoning for Q17.)

Chemistry 2023 Objective — Question 40

Positive ions in a sea of electrons are found in

  • A. covalent bonds
  • B. dative bonds
  • C. ionic bonds
  • D. metallic bondsCorrect

Explanation

In a metallic bond, there is collective sharing of a 'sea' of delocalised valence electrons among positively charged metal ions.

Chemistry 2023 Objective — Question 41

Dilute trioxonitrate (V) acid does not produce hydrogen when it reacts with metals because

  • A. it is a strong oxidizing agentCorrect
  • B. it reacts with the product
  • C. there is no visible reaction
  • D. it is highly corrosive

Explanation

HNO3 does not liberate hydrogen gas when it reacts with metals (unlike other acids) because it is a strong oxidizing agent — any hydrogen formed is immediately oxidized to water.

Chemistry 2023 Objective — Question 42

How many moles are there in 3.0 g of O3? [O=16.0]

  • A. 0.0093
  • B. 0.0930
  • C. 0.6250
  • D. 0.0625Correct

Explanation

Molar mass of O3 = 16×3 = 48 g/mol. Mole = 3 g ÷ 48 g/mol = 0.0625 mol.

Chemistry 2023 Objective — Question 43

Copper (II) ions are able to participate in co-ordinate covalent bonding because they

  • A. are coloured
  • B. have unpaired electrons
  • C. have vacant d-orbitalsCorrect
  • D. are positively charged

Explanation

Copper (II) ions can participate in co-ordinate (dative) covalent bonding because they have vacant d-orbitals that can accept electron pairs.

Chemistry 2023 Objective — Question 44

Determine the volume of 0.100 mol of HCl in 0.250 mol dm⁻³ solution.

  • A. 20 cm3
  • B. 100 cm3
  • C. 200 cm3
  • D. 400 cm3Correct

Explanation

Mole = Concentration (mol dm⁻³) × Volume (dm3). 0.1 mol = 0.25 mol dm⁻³ × V, so V = 0.1/0.25 = 0.4 dm3 = 400 cm3.

Chemistry 2023 Objective — Question 45

Which of the statements about gases is not correct?

  • A. The total kinetic energy of the gas is not affected by collision
  • B. Molecules of the gas are in constant motion
  • C. Gases have low densities compared to solids and liquids of equal mass
  • D. Gases are highly soluble in water at high temperaturesCorrect

Explanation

Unlike most solids, the solubility of most gases in water decreases as temperature increases (and vice versa) — so option D is the incorrect statement.

Chemistry 2023 Objective — Question 46

Arrange the following compounds in decreasing order of their boiling points: NH3, HF, SiH4, CH4

  • A. NH3, CH4, SiH4, HF
  • B. CH4, SiH4, NH3, HF
  • C. HF, NH3, SiH4, CH4Correct
  • D. CH4, SiH4, HF, NH3

Explanation

NH3 and HF have higher boiling points than SiH4 and CH4 because NH3 and HF exhibit hydrogen bonding. HF has the strongest hydrogen bonding of common substances, so its boiling point is higher than NH3's. SiH4 has a higher boiling point than CH4 because it is heavier. Decreasing order: HF > NH3 > SiH4 > CH4.

Chemistry 2023 Objective — Question 47

The following statements are correct except

  • A. energy is released when liquids change to solids
  • B. particles move faster in the gaseous state than in the liquid state
  • C. carbon atoms in gaseous methane are further apart than those in solid diamond
  • D. there is a large decrease in the volume of a solid metal when pressure is applied to itCorrect

Explanation

Solids are substantially incompressible, so a large decrease in volume is not expected when pressure is applied to a solid metal — option D is incorrect.

Chemistry 2023 Objective — Question 48

The vapour density of an organic compound with the molecular formula C2H4O2 is [H=1.0, C=12.0, O=16.0]

  • A. 120
  • B. 65
  • C. 40
  • D. 30Correct

Explanation

C2H4O2 = (12×2)+(1×4)+(16×2) = 60. Vapour density = ½ × RMM = ½ × 60 = 30.

Chemistry 2023 Objective — Question 49

A mixture containing two salts of different solubility can be separated by

  • A. chromatography
  • B. distillation
  • C. crystallizationCorrect
  • D. evaporation

Explanation

A mixture of two salts with different solubilities can be separated by fractional crystallization.

Chemistry 2023 Objective — Question 50

The separation technique that is suitable for separating iodine from tetrachloromethane is

  • A. solvent extractionCorrect
  • B. distillation
  • C. fractional distillation
  • D. filtration

Explanation

Solvent extraction is a separation technique that relies on the differential solubility of a substance in two immiscible solvents — suitable for separating iodine dissolved in tetrachloromethane.

Advertisement

Sign up free to unlock

  • Score tracking
  • Practice history
  • Saved questions
  • Progress dashboard
  • Personalized sessions
  • Weak-topic breakdown

…and/or go further with premium services and No Ads.