Question

7. A body of mass 18 kg is suspended by an inextensible string from a rigid support and is pulled by a horizontal force F until the angle of inclination of the string to the vertical is 35°. If the system is in equilibrium, calculate the:
(a) value of F;
(b) tension in the string. [Take g=10ms⁻²]

Accepted Answer

Resolving vertically: T cos35° = mg = 18×10 = 180N, so T = 180/cos35° ≈ 219.74N.
Resolving horizontally: F = T sin35° = 180 tan35° ≈ 126.04N.
(a) F ≈ 126.04N
(b) T ≈ 219.74N

WAEC Further Mathematics 2022 Theory — Question 7

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