WAEC Further Mathematics 2025 Theory — Question 4

Question 4 of 16 from the West African Examinations Council (WAEC) Further Mathematics 2025 Theory paper, with the correct answer and a full explanation.

4. Resolve (2x-7)/(25x-24-6x²) into partial fractions.

Model answer

Factorise the denominator: 25x-24-6x² = -(6x²-25x+24) = -(2x-3)(3x-8), so the fraction becomes (7-2x)/[(2x-3)(3x-8)]. Writing 7-2x = A(3x-8)+B(2x-3) and solving (using x=8/3 and x=3/2) gives A=-8/7 and B=5/7. So the partial fractions are: -8/[7(2x-3)] + 5/[7(3x-8)].

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