Question

6. If two fair dice are thrown twice, find the probability of obtaining a product of six in the first throw and a sum of eight in the second throw.

Accepted Answer

There are 36 equally likely outcomes per throw. P(product of 6 in first throw): pairs (1,6),(6,1),(2,3),(3,2) = 4/36 = 1/9. P(sum of 8 in second throw): pairs (2,6),(6,2),(3,5),(5,3),(4,4) = 5/36. Required probability = (1/9) × (5/36) = 5/324.

WAEC Further Mathematics 2025 Theory — Question 6

Sign up free to unlock