WAEC Mathematics 2013 Objective — Question 11
Question 11 of 50 from the West African Examinations Council (WAEC) Mathematics 2013 Objective paper, with the correct answer and a full explanation.
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Make p the subject of the relationship: q = 3p/r + s/2
- A. p=(2q−rs)/6
- B. p=2qr−sr−3
- C. p=(2qr−s)/6
- D. p=(2qr−rs)/6Correct
Explanation
q = 3p/r + s/2. Multiply through by 2r: 2qr = 6p + rs. So 6p = 2qr−rs, p = (2qr−rs)/6.
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