WAEC Physics 2012 Objective — Question 38

Question 38 of 50 from the West African Examinations Council (WAEC) Physics 2012 Objective paper, with the correct answer and a full explanation.

[Circuit diagram: 2μF and 6μF capacitors in parallel, in series with another 2μF capacitor, connected to a 10V source] Calculate the total charge in the circuit.

A. A. 80C
B. B. 35μC
C. C. 20μC
D. D. 16μCCorrect

Explanation

Parallel combination: C1 = 2μF + 6μF = 8μF. Total capacitance in series with the other 2μF: 1/CT = 1/8 + 1/2 = 5/8, so CT = 8/5 = 1.6μF. Total charge Q = CT x V = 1.6 x 10 = 16μC.

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